SELECT T0."_ID",T0."ALBUMID",T0."PHOTOID" , T."_ID",T."SYSID",T."FILENAME",T."FILEPATH",T."FILESIZE",T."FILETYPE",T."MODIFIEDTIME",T."SHOOTTIME",T."WIDTH",T."HEIGHT",T."LONGITUDE",T."LATITUDE",T."DURATION",T."ENCRYPTPATH",T."ISMOVED",T."CITY" FROM CLASSIFIES_PHOTO T0 LEFT JOIN PHOTO T ON T."_ID"=T0."PHOTOID"
4条回答 默认 最新
- Tsui丶 2017-08-11 07:05关注
SELECT T0."_ID", T0."ALBUMID", T0."PHOTOID", T."_ID", T."SYSID", T."FILENAME", T."FILEPATH", T."FILESIZE", T."FILETYPE", T."MODIFIEDTIME", T."SHOOTTIME", T."WIDTH", T."HEIGHT", T."LONGITUDE", T."LATITUDE", T."DURATION", T."ENCRYPTPATH", T."ISMOVED", T."CITY" FROM CLASSIFIES_PHOTO T0 LEFT JOIN PHOTO T ON T."_ID" = T0."PHOTOID"
这样不是看的很清楚吗? 这不就是一条查询语句吗? 左连接 返回左边的结果集,并根据ON后面条件返回右边结果集 PHOTO
本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报