int * 不能用索引赋值吗

Question

int num;
int *phones = new int[7];
phones[0] = 1;
phones[1] = 1;
phones[2] = 1;
phones[3] = 1;
phones[4] = 1;
phones[5] = 1;
phones[6] = 1;
cout << phones << endl;
system("pause");
return 0;
结果赋值无效

Answer 1

cout << phones[0] << endl;
这么写

可以赋值