一段网页获取的代码，该如何解析

Question

style="float:left; width:8px; height:8px;margin-left:17px;margin-right:
15px;margin-top:3px;">
title="ABCDEFG"target="_blank">ABCDEFG

(2017-07-16)

主要想获取title 和链接

Answer 1

用正则抓取图片链接
$subject = '

<img src="/images/jiantou.jpg" border="0px" style="float:left; width:8px; height:8px';
$pattern = '/<img[\s]*src\=\"([\s\S.]*?)\"/';

    if(preg_match($pattern, $subject,$matchs)){
        dump($matchs);
    }else{
        echo 'no';
    }       

    结果：array(2) {

[0] => string(30) " [1] => string(19) "/images/jiantou.jpg" //捕获的链接
}