配置文件：
```<!-- 执行调度任务业务类 -->
<!-- 配置执行类和方法 -->
<bean id="consultJobDetail" class="org.springframework.scheduling.quartz.MethodInvokingJobDetailFactoryBean">
<property name="targetObject" ref="consultJob"></property>
<property name="targetMethod" value="consultTypeCopy"></property>
<property name="concurrent" value="false"></property>
</bean>
<!-- 配置定时执行时间 -->
<bean id="consultTrigger" class="org.springframework.scheduling.quartz.CronTriggerFactoryBean">
<property name="jobDetail" ref="consultJobDetail"></property>
<property name="cronExpression">
<value>0/10 * * * * ?</value>
</property>
</bean>
<!-- 配置调度资源 -->
<bean class="org.springframework.scheduling.quartz.SchedulerFactoryBean"
lazy-init="false" autowire="no">
<property name="autoStartup" value="true"></property>
<property name="startupDelay" value="0"/>
<property name="triggers">
<list>
<ref local="consultTrigger"/>
</list>
</property>
</bean>
报错信息：
```Caused by: org.quartz.JobPersistenceException: The job (DEFAULT.consultJobDetail) referenced by the trigger does not exist.
at org.quartz.simpl.RAMJobStore.storeTrigger(RAMJobStore.java:422)
at org.quartz.core.QuartzScheduler.scheduleJob(QuartzScheduler.java:932)
at org.quartz.impl.StdScheduler.scheduleJob(StdScheduler.java:258)
at org.springframework.scheduling.quartz.SchedulerAccessor.addTriggerToScheduler(SchedulerAccessor.java:312)
at org.springframework.scheduling.quartz.SchedulerAccessor.registerJobsAndTriggers(SchedulerAccessor.java:235)
at org.springframework.scheduling.quartz.SchedulerFactoryBean.afterPropertiesSet(SchedulerFactoryBean.java:512)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1637)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1574)
... 57 more
使用 RAMJobStore 模式，不需要持久化到数据，启动时抛出如上异常？求解答！！
