为什么用python模拟ajax请求，得到的不是数据，是脚本，同样的url和参数，浏览器请求就可以得到数据，还需要设置什么参数吗？

Question

代码：

import requests

from urllib.parse import urlencode

def get_data():

   url = 'https://d.weibo.com/p/aj/discover/loading?'

   headers = {

   'Host':'d.weibo.com' ,

   'User_Agent':'Mozilla/5.0 (Windows NT 10.0; Win64; x64)' +

      'AppleWebKit/537.36 (KHTML, like Gecko) Chrome/79.0.3945.13' +

      'Safari/537.36' ,

   'X-Requests-With':'XMLHttpRequest' ,

   'Referer':'https://d.weibo.com/623751_5'

   }

   params = {

   'ajwvr': '6' ,

   'id': '623751_5' ,

   'uid': '7286855640',

   'page': '8' ,

   '__rnd': '1582696930127'

   }

   try:

      print(url + urlencode(params))

      response = requests.get(url + urlencode(params) , headers)

      if response.status_code == 200:

         print(response.text)

   except requests.ConnectionError as e:

      e.track()

get_data()

结果：

谷歌浏览器请求这个：

https://d.weibo.com/p/aj/discover/loading?ajwvr=6&id=623751_5&uid=7286855640&page=8&__rnd=1582696930127

结果：

Answer 1

想起来了，发送请求的时候没有验证登录，浏览器请求的是已经验证了的，哈哈哈，尴尬