//递归程序
public class DgDemo {
@Test
public void test(){
//id,name,pid,pids,pidsName
//ID,名称,父ID,所有父ID,所有父ID名称
Node node = new Node("1", "DG1", "2", "", ""); //node 与node2互为父子关系,为错误数据
Node node2 = new Node("2", "DG2", "1", "", "");
Node node22 = new Node("0", "DG0", "3", "", "");
Node node3 = new Node("3", "DG3", "4", "", "");
Node node4 = new Node("4", "DG4", "5", "", "");
List<Node> nodes2 = new ArrayList<>();
nodes2.add(node22);
nodes2.add(node3);
nodes2.add(node);
nodes2.add(node2);
nodes2.add(node4);
//上述add顺序 则是可以得到我要结果 若将node2和node4互换位置后。结果是错了的,递归node2应该返回[] 但是我使用list的清空方法。但是没清到
for (Node n : nodes2) {
System.out.println("id:"+n.getId());
List<Node> childMenu = new DgDemo().getParentId(nodes2,n.getId());
System.out.println("childMenu:"+childMenu);
}
}
private List<Node> childMenu = new ArrayList<Node>();
//设置count是防止错误数据无限循环。抛出堆栈溢出异常 终止程序
private int count = 0;
public List<Node> getParentId(final List<Node> nodes, String id) {
System.out.println(count);
if (nodes != null && nodes.size() != 0) {
for (Node node : nodes) {
if (count > 15) {
// childMenu.removeAll(childMenu);
// childMenu.clear();
Iterator it = childMenu.iterator();
while (it.hasNext()) {
it.next();
it.remove();
}
continue;
}else if (node.getId().equals(id) && count <= 15) {
if (node.getParentId().equals(node.getId())) {
childMenu.add(node);
} else if (null != node.getParentId() && !node.getParentId().equals(node.getId())) {
count++;
getParentId(nodes, node.getParentId());
childMenu.add(node);
} else {
continue;
}
}else {
continue;
}
}
}
return childMenu;
}
}
//求教大神