在java中如何把java.util.Array转化为scala.Array?

Question

如题，不知道为什么spark.mllib.classification.SVMWithSGD里要的参数是scala.Array....

Answer 1

import scala.collection.JavaConverters._

val list: java.util.List[Int] = Seq(1,2,3,4).asJava
val buffer: scala.collection.mutable.Buffer[Int] = list.asScala

http://blog.csdn.net/dymkkj/article/details/77921573
http://blog.csdn.net/ainidong2005/article/details/53121193