Linux系统下C语言编程，printf调用触发断言！

Question

各路大牛晚上好！

小弟初次在Linux系统下尝试进行C语音编程，不太顺利！调用一个printf函数，就触发了断言！

折腾了一晚上了，实在没办法了，请大牛帮忙走查一下代码，帮忙看下为什么会触发断言呢？又应当如何修改呢？先谢谢了！

代码如下：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include "init_array.h"

int variable_length_array(int **parray, int length)
{
    if (*parray != NULL)
    {
        fprintf(stderr, "The array not initiated!\n");
        return FAIL;
    }

    if (length <=0)
    {
        fprintf(stderr, "The length error!\n");
        return FAIL;
    }

    *parray = (int *)malloc(length);
    memset(*parray, 0x00, sizeof(int) * length);
    return SUCC;
}

int main(int argv, char *argc[])
{
    int *array = NULL;
    int length = 0;

    scanf("%d", &length);

    if (variable_length_array(&array, length) == SUCC)
    {
        for (int i = 0; i < length; i++)
        {
            printf("The index: %d, the content: %d, the address: %p.\n", i, array[i], array + i); // 断言所在行!
        }
    }
    else
    {
        fprintf(stderr, "Initiate array fail!\n");
        return 1;
    }
    return 0;
}

断言信息如下：
init_array.out: malloc.c:2427: sysmalloc: Assertion `(old_top == initial_top (av) && old_size == 0) || ((unsigned long) (old_size) >= MINSIZE && prev_inuse (old_top) && ((unsigned long) old_end & (pagesize - 1)) == 0)' failed.
Aborted

Answer 1

除了看出你没释放内存之外，并没啥问题