const char *,char *,char const *中vs错误问题，求指教

Question

int spitstring(const char *str, char c, char buf[10][30], int *count)//14 行
{
if (str == NULL || buf == NULL || count == NULL)
return -1;
const char *start = str;//18行
char *p = NULL;
int i = 0;
do
{
p = strchr(start, c);
if (p != NULL)
{
int len = p - start;
if (len > 0)
{
底下不写了
}}while (*start);//41行
底下不写了

    int main(void)

{
const char *p = "abcdef,acccd,eeee,aaaa,e3eeee,ssss,";
char buf[10][30] = { 0 };
int n = 0;
int ret = 0;
int i = 0;

ret = spitstring(p, ',', buf, &n);

    错误  1   error C2143: 语法错误 : 缺少“;”(在“const”的前面)  18行
    错误  16  error C2100: 非法的间接寻址  41行

把const char *换成const char *或者char *错误都消失
这种错误只在vs中存在，linux中编译无此错误
求指教

Answer 1

你定义变量太靠后了，我给你修改了

 #include <stdio.h>
#include <string.h>
#include <Windows.h>

int spitstring(const char *str, char c, char buf[10][30], int *count)
{
    const char *start = str;
    char *p = NULL;
    int i = 0;
    if (str == NULL || buf == NULL || count == NULL)
        return -1;
    start = str;
    do
    {
        p = strchr(start, c);
        if (p != NULL)
        {
            int len = p - start;
            if (len > 0)
            {
                strncpy(buf[i], start, len);
                buf[i][len] = 0;
                i++;
            }
            start = p + 1; 
        }
        else
        {
            strcpy(buf[i], start);
            i++;
            break;
        }
    } while (*start);

    if (i == 0)
    {
        strcpy(buf[i], start);
        return -2;
    }

    *count = i;
    return 0;
}

int main(void)
{
    const char *p = "abcdef,acccd,eeee,aaaa,e3eeee,ssss,";
    char buf[10][30] = { 0 };
    int n = 0;
    int ret = 0;
    int i = 0;

    ret = spitstring(p, ',', buf, &n);
    if (ret != 0)
    {
        printf("error:%d\n", ret);

        return ret;
    }

    for (i = 0; i < n; i++)
    {
        printf("%s\n", buf[i]);
    }

    system("pause");

    return 0;
}