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qq_27038979 2017-12-05 06:20关注SELECT
c.CNAME,
COUNT(DISTINCT s.SNO) AS '选修人数'
FROM
score s
RIGHT JOIN course c
ON s.CNO= c.CNO
GROUP BY c.CNAME本回答被题主选为最佳回答 , 对您是否有帮助呢?评论 打赏 举报解决 1无用
SELECT
c.CNAME,
COUNT(DISTINCT s.SNO) AS '选修人数'
FROM
score s
RIGHT JOIN course c
ON s.CNO = c.CNO
GROUP BY c.CNAME