qq_37830604 2017-12-06 02:25 采纳率: 50%
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已结题

hibernate的criteria查询

 public List<Record> list(String confID, String srcpath, Date dateTime,
            int quality, int videoBackground, int transparency, int layoutId) {
        Criteria criteria = this.sessionFactory.getCurrentSession().createCriteria(Record.class,"re");
        criteria.add(Restrictions.eq("re.confid", "a83ec67f04934c1f8648f892f3b5ea30"));
        criteria.add(Restrictions.eq("re.srcpath","d://movie"));
        criteria.add(Restrictions.eq("re.transcode_start_time","2017-11-16 13:50:13"));
        criteria.createAlias("re.rc", "rrc",CriteriaSpecification.LEFT_JOIN);//关联主对象中的附属对象的属性名
        criteria.add(Restrictions.eq("rrc.quality",1));
        criteria.add(Restrictions.eq("rrc.video_background",1));
        criteria.add(Restrictions.eq("rrc.transparency",1));
        criteria.add(Restrictions.eq("re.layoutId",1));
        criteria.setFetchMode("rrc",FetchMode.JOIN);
        List<Record> list = criteria.list(); 
        for(Record re:list){
            System.out.println("11123"+re.getLayoutid());
        }
        return (List<Record>)criteria.list();
    }
``` 现遇问题, 控制台不能show_sql,也不报错。对应的sql语句在数据库中能查询数据。

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5条回答 默认 最新

  • foralllove 2017-12-06 08:24
    关注

    System.out.println("11123"+re.getLayoutid());打印了吗?

    评论

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