AJAX的URL怎么写能被web.xml的servlet扫描到

Question

AJAX的URL怎么写能被web.xml的servlet扫描到，servlet怎么指向具体类具体方法，求一套完整demo

Answer 1

js里面 $.ajax({
url:'<%=path%>/HelloServlet',
dataType: "json",
data:{
name:"zhangsan",
password:"123123"
},
type :'GET',
success:function(data)
{
alert( $(data).get(0).name);
}
});
web.xml中

HelloServlet
com.milk.servlet.HelloServlet

HelloServlet
/HelloServlet

HelloServlet中
public void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException
{
System.out.println("执行了-------------");
String name = (String)request.getParameter("name");
String password = (String)request.getParameter("password");

System.out.println(name + " ," + password);

    student stu = new student();        
    stu.setAge(18);
    stu.setName("zhangsan");
    JSONArray arr=JSONArray.fromObject(stu);
    PrintWriter out = response.getWriter();
    out.println(arr.toString());    
    out.flush();
    out.close();
}