1个回答

knn猫狗识别算法中样本为0报错

Discount 折扣的算法问题
Problem Description All the shops use discount to attract customers, but some shops doesn’t give direct discount on their goods, instead, they give discount only when you bought more than a certain amount of goods. Assume a shop offers a 20% off if your bill is more than 100 yuan, and with more than 500 yuan, you can get a 40% off. After you have chosen a good of 400 yuan, the best suggestion for you is to take something else to reach 500 yuan and get the 40% off. For the customers’ convenience, the shops often offer some low-price and useful items just for reaching such a condition. But there are still many customers complain that they can’t reach exactly the budget they want. So, the manager wants to know, with the items they offer, what is the minimum budget that cannot be reached. In addition, although the items are very useful, no one wants to buy the same thing twice. Input The input consists several testcases. The first line contains one integer N (1 <= N <= 1000), the number of items available. The second line contains N integers Pi (0 <= Pi <= 10000), represent the ith item’s price. Output Print one integer, the minimum budget that cannot be reached. Sample Input 4 1 2 3 4 Sample Output 11
This time, two, not one 算法的问题
Problem Description I konw you guys have solve so many problems about increasing sequence, this time, a little change has been made. Assume that there is a sequence S = {s1, s2, s3, ..., sn}, si = (xi, yi).You should find two increasing subsequence L1 and L2, and they have no common elements, means L1∩L2 = φ, and the sum of their lenth is as max as possible. Here we assume si > sj is that (xi > xj && yi > yj) or (xi >= xj && yi > yj) or (xi > xj && yi >= yj). I will ensure that all elements' coordinates are distinct, i.e., si != sj (i!=j). Input The input consists of multiple test cases. Each case begins with a line containing a positive integer n that is the length of the sequence S, the next n lines each contains a pair integers (xi, yi), i = 1,...n.1 <= n <= 5000,1<=xi,yi<=2^31. Output For each test case, output one line containing the the maximum sum of the two increasing subsequence L1 and L2 you can find. Sample Input 3 1 3 3 1 2 2 4 1 2 2 1 4 3 3 4 Sample Output 2 4

Java学习的正确打开方式

linux系列之常用运维命令整理笔录

Vue + Spring Boot 项目实战（十四）：用户认证方案与完善的访问拦截

Python十大装B语法
Python 是一种代表简单思想的语言，其语法相对简单，很容易上手。不过，如果就此小视 Python 语法的精妙和深邃，那就大错特错了。本文精心筛选了最能展现 Python 语法之精妙的十个知识点，并附上详细的实例代码。如能在实战中融会贯通、灵活使用，必将使代码更为精炼、高效，同时也会极大提升代码B格，使之看上去更老练，读起来更优雅。

2019年11月中国大陆编程语言排行榜
2019年11月2日，我统计了某招聘网站，获得有效程序员招聘数据9万条。针对招聘信息，提取编程语言关键字，并统计如下： 编程语言比例 rank pl_ percentage 1 java 33.62% 2 cpp 16.42% 3 c_sharp 12.82% 4 javascript 12.31% 5 python 7.93% 6 go 7.25% 7 p...

SQL-小白最佳入门sql查询一

“狗屁不通文章生成器”登顶GitHub热榜，分分钟写出万字形式主义大作

《程序人生》系列-这个程序员只用了20行代码就拿了冠军

11月8日，由中国信息通信研究院、中国通信标准化协会、中国互联网协会、可信区块链推进计划联合主办，科技行者协办的2019可信区块链峰会将在北京悠唐皇冠假日酒店开幕。 　　区块链技术被认为是继蒸汽机、电力、互联网之后，下一代颠覆性的核心技术。如果说蒸汽机释放了人类的生产力，电力解决了人类基本的生活需求，互联网彻底改变了信息传递的方式，区块链作为构造信任的技术有重要的价值。 　　1...

【技巧总结】位运算装逼指南

《C++ Primer》学习笔记（六）：C++模块设计——函数

8年经验面试官详解 Java 面试秘诀

1.两种思维方式在求职面试中，经常会考察这种问题：北京有多少量特斯拉汽车？某胡同口的煎饼摊一年能卖出多少个煎饼？深圳有多少个产品经理？一辆公交车里能装下多少个乒乓球？一个正常成年人有多少根头发？这类估算问题，被称为费米问题，是以科学家费米命名的。为什么面试会问这种问题呢？这类问题能把两类人清楚地区分出来。一类是具有文科思维的人，擅长赞叹和模糊想象，它主要依靠的是人的第一反应和直觉，比如小孩...
so easy！ 10行代码写个"狗屁不通"文章生成器