import java.util.Scanner;
public class Main {
public String strBinary(String s) {
StringBuffer sBuffer = new StringBuffer();
for(int i = 0;i<s.length();i++) {
switch(s.charAt(i))
{
case '1' : sBuffer.append("0001");break;
case '2' : sBuffer.append("0010");break;
case '3' : sBuffer.append("0011");break;
case '4': sBuffer.append("0100");break;
case '5': sBuffer.append("0101");break;
case '6': sBuffer.append("0110");break;
case '7': sBuffer.append("0111");break;
case '8': sBuffer.append("1000");break;
case '9': sBuffer.append("1001");break;
case 'A': sBuffer.append("1010");break;
case 'B': sBuffer.append("1011");break;
case 'C': sBuffer.append("1100");break;
case 'D': sBuffer.append("1101");break;
case 'E': sBuffer.append("1110");break;
case 'F': sBuffer.append("1111");break;
default: break;
}
}
return sBuffer.toString();
}
public String strOcatal(String s) {
int k = 0;
StringBuffer stb = new StringBuffer();
if (s.substring(0, 3).equals("000")) k = 3;else k = 0;
for(int i = k;i<s.length()-2;i+=3) {
switch (Integer.valueOf(s.substring(i,i+3)))
{
case 000 : stb.append("0");break;
case 001 : stb.append("1");break;
case 010 : stb.append("2");break;
case 011 : stb.append("3");break;
case 100 : stb.append("4");break;
case 101 : stb.append("5");break;
case 110 : stb.append("6");break;
case 111 : stb.append("7");break;
}
}
return stb.toString();
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int n = in.nextInt();
Main xMain = new Main();
String str[] = new String[n+1];
for(int i = 0;i<n;i++) {
str[i] = in.next();
}
in.close();
for(int i = 0;i<n;i++) {
String x =xMain.strBinary(str[i]);
if ((x.length()%3)==1) x = "00"+x;
if ((x.length()%3)==2) x = "0"+x;
String y = xMain.strOcatal(x);
System.out.println(y);
}
}}
代码如上
蓝桥的输入数据很变态超长,但是题目中给出的数据都能成功,不明白错误在哪,诚心请求大佬指教