php注册登录后台无响应，

Question

php代码：
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "test";
//创建连接
$conn = mysqli_connect($servername,$username,$password);
if ($conn) {
// $conn->query("SET NAMES 'UTF8'");
mysqli_select_db($conn,$dbname);
$sql = "select user_id,user_pass FROM user where user_id = '$_POST[username]' and user_pass='$_POST[password]'";

    $result = mysqli_query($conn,$sql);


    // $rows=mysqli_num_rows($result);

    $arr = array();

    // var_dump($rows);
    if($result){
       $arr['result'] = 1 ;
       $arr['data'] = '登陆成功';
       exit;
    }else{
           $arr['result'] = 0;
           $arr['data'] = '用户名或密码不正确';
           exit;
         }

    // echo $result-> fetch_object() -> memTotal;
    echo json_encode($arr);
}
 $conn->close();

    ajax代码：
      mui.ajax('http://127.0.0.1/electrombile/index.php',{
                data:{
                    username:username.value,
                    password:password.value
                },
                dataType:'jsonp',               ![图片说明](https://img-ask.csdn.net/upload/201803/16/1521170353_498205.png)
                type:'POST',
                timeout:10000,
                success:function(data){
                    //{"reslut":1}

                // var data=eval("("+data+")");
                    console.log(data);
                    if(data.result == 1){
                        //登录成功
                       alert("登录成功");
                        mui.openWindow({
                            url:'mainShow.html',
                            id:'mainShow'
                        })
                    }else{
                        //登录失败
                        alert("登陆失败");  
                    }
                },
                error:function(){
                    alert("请求异常");
                }
            })

Answer 1

@u014358056，在双引号里面的单引号内，变量是会解析的。@qq_35318529 楼上回答exit是正确的，你把exit去掉，它是直接退出程序中止运行的，另外即然else了，也不需要再跳出if，这样即是输错密码，也会返回mui前端result=0