求大佬帮我看看一个关于select 下拉框的恶心问题 5C

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我给select标签以$(selecterId).attr("multiple","multiple");的方式设置让它可以多选,
但我要它没点编辑时不能被点击所以我设置了一个属性 disabled="disabled",但是我点击编辑remove掉disabled属性时,下拉框任然不能点击。
给我一种设置了disabled就不能设置multiple的感觉,求大佬帮我看看。

2个回答

你这个明显不是原生的select,用的第三方组件来处理的生成的UI,自己用组件的api来操作UI的界面,而不是直接操作原生的select对象,操作原生select对象一般不会更新组件UI的

1.select标签没有multiple这个属性
2.你设置的这个属性应该是通过你的框架设置的一个属性值
3.所以你要看你的框架在remove报错,有没有设置到具体的checkbox标签上

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i < 4; i++)rn rn list::iterator it = thestu.begin(); //定义迭代器指针rn Student stu;rn while (it != thestu.end())rn rn stu = *it;rn if (min[i] > stu.stuscore[i])rn min[i] = stu.stuscore[i];rn it++;rn rn rn cout << "各科的最低分 :" << "大外" << min[0] << "高数" << min[1] << "模电" << min[2] << "面向对象" << min[3] << endl;rnrnrn//Class.cpprnrnvoid Class::CPrint() //输出班级信息rnrn cout << setw(3) << "年级" << setw(10) << "班级" << endl;rn cout << setw(3) << clgrade << setw(10) << clclass << endl;rn cout << setw(3) << "序号";rn cout << setw(10) << "姓名" << setw(20) << "学号"\rn << setw(6) << "大外" << setw(6) << "高数"\rn << setw(6) << "模电" << setw(10) << "面向对象"\rn << setw(10) << "总分" << endl;rn list::iterator it = cl.begin();//定义迭代器指针rn int i = 0;rnrn while (it != cl.end())rn rn it->print(++i);rn it++;rn rnrnrn//ClList.cpprnrnvoid ClList::CAdd(Class cl) //增加班级信息rnrn thecl.push_back(cl);rnrnvoid ClList::CSeek(char* cclass) //查询班级信息rnrn int sign = -1;rn list::iterator it = thecl.begin(); //定义迭代器指针rn Class cl;rn while (it != thecl.end())rn rn cl = *it;rn if (strcmp(cl.Getclclass(), cclass) == 0)rn rn sign = 1;rn break;rn rn it++;rn rn if (sign > 0)rn rn cout << "查找的结果为" << endl;rn cl.CPrint();rn rn elsern cout << "没有查找到!" << endl;rnrnvoid ClList::CModify(char* cclass, Class& cl) //修改班级信息rnrn list::iterator it = thecl.begin(); //定义迭代器指针rnrn while (it != thecl.end())rn rnrn if (strcmp((*it).Getclclass(), cclass) == 0)rn rn *it = cl;rn // sign = 1;rn break;rn rn it++;rn rn cout << "修改的结果为" << endl;rn cl.CPrint();rnrnvoid ClList::CDelete(char* cclass) //班级的删除rnrn list::iterator it = thecl.begin();//定义迭代器指针rn while (it != thecl.end())rn rnrn if (strcmp((*it).Getclclass(), cclass) == 0)rn rn thecl.erase(it);rn break;rn rn it++;rn rn cout << "删除成功" << endl;rnrnvoid ClList::CShow() //年级中所有班级的显示rnrn list::iterator it = thecl.begin(); //定义迭代器指针rn Class cl;rn while (it != thecl.end())rn rn cl = *it;rn cl.CPrint();rn it++;rn rnint main() //主函数rnrn StuList thestu; //存放所有学生rn Student stu1("ma", "0803070201", 88, 90, 69, 52.6f);rn Student stu2("li", "0803070202", 52, 96, 74, 56);rn Student stu3("wang", "0803070101", 85, 25, 95, 79);rn Student stu4("yang", "0803070102", 82, 78, 84, 95);rn Student stu5("ding", "0803070301", 76, 85.6f, 94, 83);rn thestu.Add(stu1);rn thestu.Add(stu2);rn thestu.Add(stu3);rn thestu.Add(stu4);rn thestu.Add(stu5);rn thestu.Show();rnrn thestu.Seek("0803070201"); //查找学号为0803070201的同学rnrn cout << "排序的结果" << endl;rn thestu.SorttoFile("student.dat"); //按总分排序rn thestu.Max();rn thestu.Min();rnrn StuList s1;rn StuList s2;rn StuList s3;rn s1.Add(stu3);rn s1.Add(stu4);rn s3.Add(stu5);rn s2.Add(stu1);rn s2.Add(stu2);rnrn ClList thecl;rnrn Class cl1("二年级", "08030701", s1.Getthestu());rn Class cl2("二年级", "08030702", s2.Getthestu());rn Class cl3("二年级", "08030703", s3.Getthestu());rn thecl.CAdd(cl1);rn thecl.CAdd(cl2);rn thecl.CShow();rn thecl.CSeek("08030702"); //查找班级为08030702的班级rn thecl.CAdd(cl3);rn cout << "将08030702修改为08030703" << endl;rn thecl.CModify("08030702", cl3); //修改班级rn cout << "删除08030701班" << endl;rn thecl.CDelete("08030701"); //删除08030701班rn return 0;rn
关于下拉框SELECT选中的问题
CS代码:[code=C#]string g_strPosition="2nd Page";[/code]rnrnaspx代码:rn[code=C#]rn rn 1st Pagern 2nd Pagern 3rd Pagern 4th Pagern 5th Pagern rn[/code]rnrn想根据strPosition变量的值在前台的下拉框selPosition的某一项选中,有什么好方法?
请教关于select下拉框的问题
我想在select中输入一个字如:毛,然后让下拉框中仅列出含“毛”的选项rn代码如下:提示网页错误,请大家帮我看一下哪错了。rn rnrn毛巾rn毛毯rn手套rn螺丝rn手机rn螺丝帽 (按ENTER键rn,然后输入汉字如‘手’,下拉框中仅出现则含”手“的选项:手套,手机。若输入错误,请按ENTER键取消,重新输入) rnrn 物品管理rnrnrn rnrnrnrn
请教 关于select下拉框的问题
rn selected>--请选择---rn selected>否rn selected>是rn rn rn使用这个出来的效果是如下:rnselected>--请选择--rnselected>是rnselected>否rnrn为什么不能出来选择只能出来这种饿,错在哪。rn
关于下拉框的问题,select 和option
就是我一个下拉框的筛选。数据可以准备的筛选出来了,比如我筛选增加操作类型的,但是点击筛选的时候下拉框的文本显示又变回请选择了,数据可以准备的筛选出来,怎么样才能下拉框给他保持显示增加呢。rn 操作类型:rn rn 请选择rn 增加rn 修改rn 删除 rn
关于数据库的问题,希望能有大佬帮我看看
一张score表,有class number name maths chinesen问题是:n人数小于20的班级的数学成绩n两个条件,班级人数小于20和他们的所有数学成绩
C语言 指针问题 求大佬帮我看看 谢谢
copy_arr(target1, source, 5);,copy_ptr(target2, source, 5);这两个函数运行完成之后都是符合要求的,但copy_ptrs(target3, source, source + 5);运行后,前面两个复制的全变成垃圾值了,是我指针用错了吗?rn [img=https://img-bbs.csdn.net/upload/201902/17/1550411754_43980.jpg][/img][img=https://img-bbs.csdn.net/upload/201902/17/1550411754_244485.jpg][/img][img=https://img-bbs.csdn.net/upload/201902/17/1550411754_465317.jpg][/img][img=https://img-bbs.csdn.net/upload/201902/17/1550411754_737454.jpg][/img]rnrn[code=c]//将source的值通过三种方法复制到target1,target2,target3里面rn//使用带数组表示法的函数进行第一份拷贝。rn//使用带指针表示法和指针递增的函数进行第二份拷贝。rn//把目标数组名、源数组名和带靠背的元素个数作为前两个函数的参数。rn//第三个函数以目标数组名,源数组名和指向源数组最后一个元素后面的元素的指针。rnrn#include rnrnvoid copy_arr(double *a, double *b, int c); rnvoid copy_ptr(double *a, double *b, int c);rnvoid copy_ptrs(double *a, double *b, double *c);rnrnint main()rnrn double source[5] = 1.1, 2.2, 3.3, 4.4, 5.5;rn double target1[5];rn double target2[5];rn double target3[5];rn int i;rn rn copy_arr(target1, source, 5);rn copy_ptr(target2, source, 5);rn copy_ptrs(target3, source, source + 5);rn for(i = 0; i < 5; i++)rn printf("%10g%10g%10g%10g\n", source[i], target1[i], target2[i], target3[i]);rn rn return 0;rn rnrnvoid copy_arr(double *a, double *b, int c)rnrn int i;rn double *p = a;rn for(i = 0; i < c; i++)rn p[i] = b[i];rnrnrnvoid copy_ptr(double *a, double *b, int c)rnrn double *p = a;rn int i;rn for(i = 0; i < c; i++, p++)rn *p = b[i];rnrnrnvoid copy_ptrs(double *a, double *b, double *c)rnrn int i;rn double *p = a;rn for(i = 0; p != c; i++, p++)rn *p = b[i];rnrn[/code]
一个关于网页游戏的问题,求大佬指教!
最近想用Java做个简单的网页游戏,但是有个问题很纠结。rnrn就是在每次跟用户交互后需要做个小计算,纠结在于这个计算是放在前端还是放在后台服务器!rnrn放前端嘛又怕数据不安全,放服务器又觉得会增大服务器负担!rnrn有没有大佬分享下经验~[img=https://forum.csdn.net/PointForum/ui/scripts/csdn/Plugin/003/monkey/12.gif][/img]
帮我看看这条select
sqlstr="select * from friend ,userinfo where rnrnfriend.user_id=userinfo.user_id and friend.id=1"rnrn老在这里报错:rs.open sqlstr,conn,1,1rnfriend ,userinfo 表分别有相同字段user_idrn
有关于下拉框select
我的一个select是列举部门的,从departmentDefine中取值rn另一个select是列举部门人员的,从employeeDefine中取值,这两个表通过department_ID联系,现在这两个下拉框在同一个页面中,我想实现随着部门下拉框的改变,其人员的下拉框也要改变,如何实现这一功能?请各位高手们帮忙!
关于el表达式出现异常,求大佬看看
现在在做数据库分页,但是在jsp上一直报错javax.el.PropertyNotFoundException: Property 'users' not found on type java.lang.Stringrn在论坛上各种找都找不到我的情况,希望大佬帮我看看rn[code=java]public class Page rn private int currentPage;//当前页rn private int totalPage;//总页数rn private int count;//每页数据的条数rn private List users;//当前页的数据rn private int totalCount;//数据总条数[/code]rnrn[code=java]rn rn rn rn rn rn rn $user.namern $user.signaturern rn rn rn rn rn rn rn rn rn rn [/code]
帮我看一恶心问题
打开模式对话框rnvar str = showModalDialog("HTMLPage.htm?temp="+Math.round(Math.random()*10000), this.id, "dialogHeight=200,dialogWidth=200,dialogLeft=100,dialogTop=400,scroll=no");rnrn然后HTMLPage.htm页面rn window.onload = function() rnif (window.dialogArguments != null) rnvar value = window.dialogArguments;rnalert(value);//能够打印出来rn$("lblUser").value = value;rn else alert("no"); rnrnrnfunction $(obj)rn return document.getElementById(obj);rnrnrn问题就是怎么不能赋值 这个lblUser标签rn还有一个问题 为撒模式窗体有时对模式窗体没作用?
JS算法 求大佬看看
var G = [];rn window._fetch = function(t, e) rn t = n(t),rn t[1] && console.log(t[1]),rn t = t[0],rn t.SourceType = _App || _mApp ? _Tool.Version.ios ? "5" : "3" : _Tool.Version.ios ? "4" : "2";rn var a, s = t.isNew = "xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx".replace(/[xy]/g, function(t) rn var e = 16 * Math.random() | 0rn , a = "x" == t ? e : 3 & e | 8;rn return a.toString(16)rn ), o = [], r = String.fromCharCode((s[_Tool.Date.DAY_TIME % 36].charCodeAt() + s[-_Tool.Date.GMT_DIF % 36].charCodeAt()) % 10 + 99);rn for (var c in t)rn "isChat" != c && (a = t[c],rn "object" === ("undefined" == typeof a ? "undefined" : (0,rn y.default)(a)) && (a = encodeURIComponent((0,rn _.default)(a))),rn "SourceType" == c && (t.isNew += r),rn o.push(c + "=" + a));rn t.append && t.append("isNew", t.isNew),rn o = o.join("&");rn for (var l = (new Date).getTime(), c = 0; c < G.length; c++)rn if (G[c].length < 3 || G[c][0] + 1e3 < l || G[c][1].indexOf("SendGift") > -1)rn G.shift(),rn c--;rn else if (G[c][1] === o)rn return rn then: function(t) rn t && t(G[c][2])rn rn ;rnrn[img=https://img-bbs.csdn.net/upload/201907/16/1563245114_460919.png][/img]rnrn求教 这个R=g 怎么计算的 r = String.fromCharCode((s[_Tool.Date.DAY_TIME % 36].charCodeAt() + s[-_Tool.Date.GMT_DIF % 36].charCodeAt()) % 10 + 99);rn看不懂JS代码 大佬指点指点 谢谢
新手求大佬帮忙看看
刚学C语言,实在没法理解。昨天自己憋了一下午,也没看出什么地方有问题。rn[code=c]#pragma warning(disable:4996)rn#includernint main()rnrn char str1[30], str2[30];rn printf("please enter string:");rn gets(str1);rn printf("which character that begin to copy? ");rn int m;rn scanf("%d", &m);rn void str_c(char x[], char y[], int n);rn str_c(str1, str2, m);rn printf("%s\n", str2);rn return 0;rnrnvoid str_c(char x[], char y[], int n)rnrn int i;rn for (i = n; i != '\0'; i++)rn rn y[i - n] = x[i];rn y[i - n] = '\0';rnrn[/code]rnrnrn后面写的str_c 函数目的是想把字符串x中第n个字符后面的复制到字符串y中去。真的无法理解为什么这么写会运行出错?rn有没有前辈解释一下哪错了?谢谢
求大佬来帮忙看看
eclipse一直报An internal error occurred during: "Computing Git status for repository hp222".Trailing char < > at index 82: C:\Users\hp222\AppData\Roaming\duowan\yy\mainframe\theme\float\star-V1-V6-apng.png
求大神帮我看看关于列表的问题
我小白,做毕业设计有点问题想向大家请教。[img=https://img-bbs.csdn.net/upload/201504/21/1429590621_309183.png][/img]这个是我想做成的目标。我现在是这个样的不知道问题出在了哪里[img=https://img-bbs.csdn.net/upload/201504/21/1429590687_193830.png][/img],请大家帮我看看。谢谢。代码如下,rnvoid CTest3Dlg::OnRead() rnrn // TODO: Add your control notification handler code herern UpdateData(); //将界面的数据更新到对应的变量中rn char *buf;rn CString str;rn GetDlgItem(IDC_EDIT1)-> GetWindowText(str); //读取码流到str字符串中rn str.Replace(_T("7E"),_T("H")); //将码流字符串中的7E替换为Hrn buf= new char[str.GetLength()+1]; //将char*转换为buf[]rn memset(buf, 0, str.GetLength()+1); //buf[]初始化rn strcpy(buf, str); //buf[]赋值rnrnCString StrNum; // 列表控件的行标rnCString strItem; //向控件中插入的字符串内容rnint i=1;rnrn char *seps="H"; //分隔符'H'rn char *token=NULL;rn token=strtok(buf,seps); //以'H'为分隔符分割字符串bufrn while(token!=NULL) rn rn strItem.Format ("%s%s%s","7E",token,"7E");rn token=strtok(NULL,seps);rn StrNum.Format(_T("%d"),i); //将整形变量i以字符型输出rn int count=m_list.GetItemCount(); //获取列表控件当前存在的数据总量rn m_list.InsertItem(count,StrNum); //插入一行rn m_list.SetItemText(count,1,strItem); //为第一列插入字符串rn rnrnrnrnrn后面的是list的代码rnm_list.InsertColumn(0, _T("序号"), 60);rnm_list.InsertColumn(1, _T("各个信令单元"), 100);rnm_list.SetColumnWidth(0, 50);//设置列宽 rnm_list.SetColumnWidth(1, 300);
大家帮我看看一个SELECT语名
我的datagride中列了两个字段是一个是否公布BYTE型的叫isSend 别一个是题目VarChar型titlernrn这语句这样写有错吗rn"SELECT title,case isSend when 1 then '公布'else'未公布' end FROM GB_LeaveWord order by isSend ASC";rnrnrnrn rnrnrnrnrnrnrn
关于SELECT 的一个问题 大家帮忙看看
我有个SQL:求一组平均数里面的最大值rnselect max(v1) from (select avg(row1) as v1 from table group by row2 )rn结果无法通过 请问有什么问题 如果要实现此功能 应该怎么改 谢谢
求大神帮我看看Date的一个问题
rn[code=java]package javase1day05;rnrnimport java.text.SimpleDateFormat;rnimport java.util.Calendar;rnimport java.util.Date;rnimport java.util.GregorianCalendar;rnrnpublic class DateCalDemo rn public static void main(String[] args) rn //时间计算的原理rn long now = System.currentTimeMillis();rn long l = now+1000L*60*60*24;//明天 rn System.out.println(l); rn SimpleDateFormat fmt = rn new SimpleDateFormat("yyyy-MM-dd");rn rn Calendar cal = new GregorianCalendar();rn cal.add(Calendar.MONTH, 5);rn System.out.println(fmt.format(cal.getTime()));rn cal.add(Calendar.YEAR, 5);//1387260478395rn System.out.println(fmt.format(cal.getTime()));rn cal.set(Calendar.DAY_OF_WEEK, Calendar.MONDAY);rn System.out.println(fmt.format(cal.getTime())); rn rn rn rn rnrnrn[/code]rn大家帮我看看,如果我注释掉这里(第二个输出)[code=java]System.out.println(fmt.format(cal.getTime()));[/code],得到的结果是2018年12月10日,但是从日历上来看应该 是2018年12月17日。如果我把fmt.format(cal.getTime())单独提出去的话,得到的结果是正确的。rn另外,如果我注释掉第一个输出[code=java]System.out.println(fmt.format(cal.getTime()));[/code],对结果却是没有影响的,rn跪求大家给我看看是为什么,难道是闰年的原因?
phpstorm的一个很恶心的问题。。求高手
描述很简单。。就是当你打开一个文件[img=http://img.my.csdn.net/uploads/201212/14/1355479229_8996.jpg][/img],各位大大,看到了吗?body的B默认是insert(插入)。。。默认的,然后我每次都要点下ins键(就是insert),才能正常使用。。。求各位大大,告诉我怎么搞。。才能不每次都这样。。。如果这样描述还不够详细。。。那我就没办法了。。语文没学好、、、好吧。我的QQ是402374739,知道的麻烦告诉我。。。小弟拜谢!!!
很恶心的一个问题!!
请看以下很简单的代码:注意 在 rn rnrn rnrnrnrnrnrnrn如果我把 放在最前面;
请教select下拉框问题
下载了的二级联动源码,想把它移植到strtut标签网页中来,相关代码如下:rn[code=html] rn rn rn rn rn 类别:rn rn rn rn 请选择主目录rn rn rn rn rn $blist.namern rn rn rn rn rn --选择子目录--rn rn rn rn rn rn [/code]rnrnrn[code=javascript] [/code]rngetChilds.jsp页面rn[code=java]<%rnString id = request.getParameter("id");rn rn CategoryDao dao = new CategoryDao();rn List cs = dao.findByHQL("from Category where directoryId="+ Integer.parseInt(id));rn rn System.out.println(cs.size());rnStringBuffer buf = new StringBuffer();rnbuf.append("document.medForm.categoryId.length = " + (cs.size()+1) + ";\n");//这里document.medForm.categoryId不知怎么修改,请高手出招rnbuf.append("document.medForm.categoryId.options[0].value = '';\n");rnbuf.append("document.medForm.categoryId.options[0].text = '--请选择--';\n");rnbuf.append("document.medForm.categoryId.selectedIndex = 0;\n");rn rnint i=0;rnfor(Iterator iter = cs.iterator(); iter.hasNext(); i++) rn Category t = (Category)iter.next();rn rn buf.append("document.medForm.categoryId.options[" + (i+1) + "].value = '" + t.getId() + "';\n");rn buf.append("document.medForm.categoryId.options[" + (i+1) + "].text = '" + t.getName() + "';\n");rnrn[/code]rn原来的代码form是有名称的rn rn现在的html:form没有medForm了,rngetChilds.jsp页面一系列的document.medForm.categoryId该怎么修改?谢谢!!
select下拉框的问题!
请教各位怎样才能教select下拉框,又能输入又能下拉选择呢?
select 下拉框问题
option 大约有几十个 为避免占空间太长 只想显示10个 其余的下拉选择rnrn用了size="10" 但向上挤了 有什么方法控制显示option个数?
select下拉框的奇怪问题
一个省市区的三级联动下拉框,都是异步加载的,更换省份后,点击城市下拉框是,下拉框展开后又迅速收了回去,然后再点击是正常的,请高手帮帮忙,这是为什么?
请教select下拉框的问题!
各位大虾,请帮帮忙。rn譬如我有下面这个select下来框rn rn Arialrn 宋体rn 黑体 rn rn我想做这么一个功能,就我获得了一个值通过判断,如果这个值与select框下面的原先的某个值相同,则将原先的这个值选中显示出来,[color=#FF0000]而如果我有一个新值譬如"楷体",我想通过js将这个"楷体"显示在select框上,而它本身项并没有改变,打开下来框,里面还是显示Arial,宋体,黑体。[/color]rn我想问这个红色部分是怎么实现的。rn谢谢!rn
jsp 下拉框select问题
品牌不限rnrn这个用法谁能帮助解释一下?那个值是带有数据的集合、是通过什么方式传过来的
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