php 返回JSON数据 如何提取数据

Question

返回的JSON数据格式是这样的

 data=%7B%22site_id%22%3A+%221596050222807053%22%2C+%22ad_id%22%3A+%22%22%2C+%22data%22%3A+%5B%7B%22lable%22%3A+%22%5Cu8bfe%5Cu7a0b%5Cu9009%5Cu62e9%22%2C+%22id%22%3A+1596050222818312%2C+%22value%22%3A+%22%5Cu897f%5Cu70b9%5Cu70d8%5Cu7119%22%2C+%22label%22%3A+%22%5Cu8bfe%5Cu7a0b%5Cu9009%5Cu62e9%22%7D%2C+%7B%22lable%22%3A+%22%5Cu59d3%5Cu540d%22%2C+%22id%22%3A+1596050222818328%2C+%22value%22%3A+%22%5Cu6d4b%5Cu8bd5%22%2C+%22label%22%3A+%22%5Cu59d3%5Cu540d%22%7D%2C+%7B%22lable%22%3A+%22%5Cu7535%5Cu8bdd%22%2C+%22id%22%3A+1596050222818344%2C+%22value%22%3A+%2213488888888%22%2C+%22label%22%3A+%22%5Cu7535%5Cu8bdd%22%7D%5D%7D

如何提取里面的姓名、电话等信息？

注:JSON是从另外一个平台提取的，前端是不能操作。

我用站长工具去 解码就可以出来，
但是直接用PHP urldecode 转换

 data={“site_id“: “1596050222807053“ “ad_id“: ““ “data“: [{“lable“: “u8bfeu7a0bu9009u62e9“ “id“: 1596050222818312 “........

符号是中文的、过滤了 \

Answer 1

你是要php提取还是js了？你这个数据时客户端提交的键值对中还是什么？客户端提交的直接
$data=$_POST["data"];获取就行了，如果是get提交用$data=$_GET["data"];
然后json_decode转为对象就可以获取了
http://www.php.net/manual/en/function.json-decode.php