[ {
"id": "510489e1acab613446b69034eada2943",
"number": "1",
"name": "模块(一)",
"superclass": "0",
"superclass_name": "无",
"higrade": "",
"lograde": "",
"remark": "",
"standard": "科学性和创新性"
},
{
"id": "b273cb4050abf959a823ff07ef95deec",
"number": "1.1",
"name": "管理方法",
"superclass": "510489e1acab613446b69034eada2943",
"superclass_name": "模块(一)",
"higrade": "10",
"lograde": "",
"remark": "",
"standard": "所应用的管理方法(技术)符合普遍性认知的科学规律,符合质量品牌管理发展趋势。"
},
{
"id": "35362a8ba4fbe04a9e23496806910dea",
"number": "1.1.1",
"name": "大萨达",
"superclass": "b273cb4050abf959a823ff07ef95deec",
"superclass_name": "管理方法",
"higrade": "",
"lograde": "",
"remark": "",
"standard": ""
},
{
"id": "1cf9f7ec5fb807d5477765c8ddb5b310",
"number": "1.2",
"name": "创新性经验",
"superclass": "510489e1acab613446b69034eada2943",
"superclass_name": "模块(一)",
"higrade": "15",
"lograde": "",
"remark": "",
"standard": "在管理方法(技术)本身或(和)应用过程中有创新性经验(成果)。"
},
{
"id": "bc230f233763864c200c465d24feb9ed",
"number": "1.3",
"name": "核心内容",
"superclass": "510489e1acab613446b69034eada2943",
"superclass_name": "模块(一)",
"higrade": "10",
"lograde": "",
"remark": "",
"standard": "能成功应用该管理方法(技术)的核心内容,且逻辑清晰,内容完整。"
}]
上面的数据格式,我新插入一条数据,新插入如果higrade 不为空,且superclass是1.1.1,如果1.1.1的higrade为空,继续找1.1.1的上一级,就是一直向上找直到找到superclass为0为止,这样的递归算法怎么写