void print_digits_backwards(int x)
{
    if (x == 0) { cout << 0; return; }
    while (x != 0)
    {
        cout << x % 10 << ' ';
        x /= 10;
    }
}

void func(int value)
{
std::string src = std::to_string(value);
for(int i=1;i<=src.length();++i)
std::cout << src[src.length() - i] << std::endl;
}

思路：转换成字符串 倒叙打印
void print_digits_backwards1(unsigned int value)
{
char strValue[1024] = {0};
itoa(value, strValue, 10);
for (int i = strlen(strValue) - 1; i >= 0; i--)
printf("%d ", strValue[i] - '0');
printf("\n");
}

思路：取余 打印，去掉最后一位循环到结束
void print_digits_backwards2(unsigned int value)
{
do{
printf("%d ", value % 10);
value /= 10;
} while (value > 0);
printf("\n");
}

可以用递归的方式

 void PrtPyDigixSth(int x){
    printf("%d",x % 10);
    x = x / 10;
    if ( x != 0 ) {
        PrtPyDigixSth(x);
    }
}

printf是函数。cout是ostream对象，和<<配合使用

void print_digits_backwards(int num)
{
    if (num == 0)
    {
        std::cout << 0;
    }
    else
    {
        while (num)
        {
            std::cout << num % 10 << ' ';
            num /= 10;
        }
    }
    std::cout << std::endl;
}

void PrtPyDigixSth(int val)
{
std::string c;
char a[20] = {};
sprintf_s(a,"%d",val);
int len = strlen(a);
for (int i = 0; i < len/2; ++i)
{
char temp = a[i];
a[i] = a[len - 1 - i];
a[len - 1 - i] = temp;
}
std::cout << a <<std::endl;
}