如下代码摘抄自c++高级编程用于展开输出tuple，其中每一个类Tuple_print_help<typename Tuple, int size>对象都构造了一个名为tu的Tuple_print_help<Tuple, size - 1>对象

template<typename Tuple, int size>
class Tuple_print_help;
template<typename Tuple>
class Tuple_print_help<Tuple, 0>
{
public:
   Tuple_print_help(const Tuple &){}
};
template<typename Tuple,int size>
class Tuple_print_help
{
public:
   Tuple_print_help(const Tuple &Tup)
   {
       Tuple_print_help<Tuple, size - 1> tu(Tup);
       std::cout << std::get<size-1>(Tup)<<std::endl;
   }
};
template<typename Tuple>
void Tuple_print(const Tuple & tup)
{
   Tuple_print_help<Tuple, std::tuple_size<Tuple>::value>tu(tup);
}

如果将代码改为如下所示却会出现错误

template<typename Tuple, int size>
class Tuple_print_help;
template<typename Tuple>
class Tuple_print_help<Tuple, 0>
{
public:
   Tuple_print_help(const Tuple &){}
};
template<typename Tuple,int size>
class Tuple_print_help
{
public:
   Tuple_print_help(const Tuple &Tup)
   {
       Tuple_print_help<Tuple, size - 1> (Tup);
       std::cout << std::get<size-1>(Tup)<<std::endl;
   }
};
template<typename Tuple>
void Tuple_print(const Tuple & tup)
{
   Tuple_print_help<Tuple, std::tuple_size<Tuple>::value>(tup);
}

如上代码使用无名对象，类 "Tuple_print_help<std::tuple<int>, 1>" 不存在默认构造函数，然而我使用非模板类的无名对象却并不会出现这种情况，

前端用webstorm开发，后台用eclipse开发，怎么将前后台结合起来？

白桦yuma

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