跪求各位大神!!python的因式分解 Time Limit Exceeded 20C

图片说明

要求输入一个整数n,输出n的所有因式分解式子。如输入n=12,则输出12=2x2x3

12=2x6 12= 3x4 12=12 具体要求见图片,我自己写的代码总是超时,哪位好心的大神帮忙看看 这题怎末破

 flag = 0
s = input()
num = int(s)
num1 = num
num2 = str(num)
s1 = []
s = num2+'='
i = 2
if num == 1:
    print('1=1')
    flag = 1
if num == 0:
    print('0=0')
    flag =1
while flag == 0:
    if num%i == 0:
        if num/i<i:
            i = num
        s1.append(int(i))
        num = num/i
        if num==1:
            s = str(num2)+'='
            for j in range(0,len(s1)):
                if j< len(s1)-1:
                    s = s+str(s1[j])+'*'
                else:
                    s = s+str(s1[j])
            print(s)
            if len(s1)>1:
                a = i * s1[len(s1)-2] 

                b = s1[len(s1)-2] 
                if a / (b+1) < (b+1):
                    s1.pop()
                    s1.pop()
                    num = a
                    i = a
                else:
                    s1.pop()
                    s1.pop()
                    b = b+1
                    while not a%b==0:
                        b = b+1
                    num = a
                    i = b
            else:
                flag=1

    else:
        i = i + 1


3个回答

把最外层的While循环改成For循环,进而减少循环深度,或许能解决你的问题。
当输入的数比较大时,你的选用的逻辑方法循环层次太深,超出了堆栈容限,机器处理不过来。

你说的超时是什么意思?如果你嫌耗时太长的话,可以想办法把print打印方式改一下,1.如果是输出到文件会大量减少你的耗时。2.拖到cmd窗口之后 在
后面加上>1.txt 这会把打印内容输入到1.txt会大量减少时间,因为print多的话是很花时间的。代码逻辑没怎么看,看着蛋疼

额,虽然不想说,但是,你这个程序运行起来没问题,唯一就是你input没给提示,所以我猜想你是不是一直在等它提示你输入啊。。。。。。

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#includen#includen#includen#includenusing namespace std;ntypedef int state[9]; nconst int maxstate=1000000;nstate st[maxstate],goal=1,2,3,4,5,6,7,8,0;nint dist[maxstate];nchar record[maxstate]; //前一个状态到这一个的移动nint father[maxstate];//记录夫节点配合record【】nint vis[362880];nint fact[9];nconst int dx[4]=-1,1,0,0;nconst int dy[4]=0,0,-1,1;nconst char dir[4]='u','d','l','r';nvoid init_lookup_table()nn fact[0]=1;n for(int i=1;i<9;i++)n fact[i]=fact[i-1]*i;nnint try_to_insert(int s) //编码nn int code=0;n for(int i=0;i<9;i++)n n int cnt=0;n for(int j=i+1;j<9;j++)n if(st[s][j]=0&&newx<3&&newy>=0&&newy<3)n n state& t=st[rear];n memcpy(&t,&s,sizeof(s));n t[newz]=s[z];n t[z]=s[newz];n dist[rear]=dist[front]+1;n if(try_to_insert(rear)) //如果这个状态未被访问n n father[rear]=front;n record[rear]=dir[d];n rear++;n n n n front++;n n return 0;nnint main(void)nn char ch[100];n int index;n while(gets(ch)!=NULL) //输入n n index=0;n memset(vis,0,sizeof(vis));n memset(dist,0,sizeof(dist));n for(int i=0;i<100;i++)n n if(ch[i]>='0'&&ch[i]<='9')n st[1][index++]=ch[i]-'0';n else if(ch[i]=='x')n st[1][index++]=0;n n int ans=bfs();n if(ans>0)n n string str;n int v=ans;n int k=dist[ans];n while(k--)n n str.push_back(record[v]); //路径生成n v=father[v];n n for(int i=str.length()-1;i>=0;i--)n printf("%c",str[i]);n printf("\n");n n elsen printf("unsolvable\n");n n return 0;nn
PAT1019 数字黑洞 提交时Time Limit Exceeded
//PAT1019V1rn#include rnrnint FeiDiZeng(int n)rn int a[4];rn a[0]=n%10; //gern a[1]=n/10%10; //shirn a[2]=n/100%10; //bairn a[3]=n/1000; //qianrn int tmp,i,j;rn for(i=0;i<3;i++)rn for(j=i+1;j<4;j++)rn if(a[i]a[j])rn tmp=a[j];rn a[j]=a[i];rn a[i]=tmp;rn rn rn rn return a[0]*1000+a[1]*100+a[2]*10+a[3]; rnrnrnint main()rn int n,a[4];rn scanf("%d",&n);rn a[0]=n%10; //gernrn a[1]=n/10%10; //shirn a[2]=n/100%10; //bairn a[3]=n/1000; //qianrnrn// if(a[0]==a[1]==a[2]==a[3]) //debugrn if(a[0]==a[1]&&a[1]==a[2]&&a[2]==a[3]) rn printf("%d - %d= 0000",n,n);rn rn elsern int FDZ=FeiDiZeng(n),FDJ=FeiDiJian(n); rn while(FDZ-FDJ!=6174)rn const int result=FDZ-FDJ;rn printf("%04d - %04d = %04d\n",FDZ,FDJ,result);rn FDZ=FeiDiZeng(result);rn FDJ=FeiDiJian(result);rn rn printf("%04d - %04d = %04d\n",FDZ,FDJ,FDZ-FDJ);rnrn rnrnrnrn```rn rn```
武大网络赛之G Time Limit Exceeded (找逆序对)
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[img=https://img-bbs.csdn.net/upload/201809/05/1536110393_136531.png][/img] include include using namespace std; class complex { public: complex(){} complex(double m,double n) { this-&amp;amp;gt...
请问可以怎样修改,以至于不会Time Limit Exceeded!!!!
数组去重排序rn#includernusing namespace std;rnvoid sort(int a[10001],int p)rn int same;rn for(int i=0;ia[j+1]) rn same=a[j+1];rn a[j+1]=a[j];rn a[j]=same;rn rn rn for(int i=0;i>n;rn int flag=1;rn for(int i=0;i>m;rn for(int j=0;j
Time to live exceeded,什么原因?
Linux下使用ping命令ping另一solaris主机,返回rnFrom 192.168.2.1 icmp_seq=0 Time to live exceededrnFrom 192.168.2.1 icmp_seq=1 Time to live exceededrnFrom 192.168.2.1 icmp_seq=2 Time to live exceededrnFrom 192.168.2.1 icmp_seq=3 Time to live exceededrn另使用telnet命令,返回rntelnet: Unable to connect to remote host: No route to hostrn----rn本人对网络什么的是菜鸟,还请各位大虾指点指点
Time to live exceeded ,什么原因?
Linux下使用ping命令ping另一solaris主机,返回 :rnFrom 192.168.2.1 icmp_seq=0 Time to live exceeded rnFrom 192.168.2.1 icmp_seq=1 Time to live exceeded rnFrom 192.168.2.1 icmp_seq=2 Time to live exceeded rnFrom 192.168.2.1 icmp_seq=3 Time to live exceeded rnrn另使用telnet命令,返回 :rntelnet: Unable to connect to remote host: No route to host rn---- rn上面是什么原因,还请各位大虾指点指点
Time to live exceeded怎么办
我在尝试做一个路由跟踪器,测试的时候抓包找到这个问题;明明可以ping通对方地址,在尝试路由跟踪的时候就会报这个问题,求大虾指点一二
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java.lang.OutOfMemoryError: GC overhead limit exceeded
在电脑上调试的时候是可以的,放在服务器上就不行了,服务器是window7,tomcat55版本,抱着个错误,代码是大概1000条数据和数据库中20w数据做比较的时候,第一次可以,第二次就不行了,重启tomcat就可以了,这是什么原因,为什么开发的时候是好好的,导入多次都没问题![img=https://forum.csdn.net/PointForum/ui/scripts/csdn/Plugin/003/monkey/35.gif][/img]
怎么解决Output Limit Exceeded
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Time Limit Exceed求助
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编程之美2015资格赛的一道题,求大神指教,为什么会time limit exceeded?
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time limit 的问题
默认程序运行是30秒超时rn当程序运行超时的时候,会出现错误rn请问如何使得程序到了超时的时候不出现错误而继续往下运行下面的代码?
各位大神 跪求sql
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zoj_1649出现Memory Limit Exceeded,各位大牛帮帮忙啊
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compiler limit : debug information module size exceeded
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gc overhead limit exceeded 解决办法和问题追究
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我用borland c++ 4.5 编程,在编译(compile)的时候通不过rn显示rnfatal:compile table limit exceededrnrn怎么回事,可能是什么问题呢,rn请指点!rn
跪求各位大神 “服务器应用程序不可用”
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acm 总是Time Limit Exceed!!!!!!!!!!!
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Python下的整数的因式分解
Python的因式分解,先上传一下代码,以后再说思路 a=int(input(‘please input a number’)) i=2 c=a ls=[] while i&lt;a: if a%i==0: a=a/i ls.append(i) i=2 else:i=i+1 ls.append(round(a)) o=1 while o&lt;len(ls): ls.insert(o,‘×’) o...
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