IBM 的AIX系统怎么不使用库生成uuid?

Question

想不安装外部库的情况下用系统工具生成uuid，找到的指令生成了，却格式不一样。

http://www.kuqin.com/aixcmds/aixcmds5/uuid_gen.htm

这个指令生成的格式似乎不对，不是应该 是8-4-4-4-12吗？
求指导，最好用系统工具生成。

Answer 1

请参考下面的方法：

To generate a character-string representation of a UUID, enter the following:
/etc/ncs/uuid_gen

This produces the following output:

34dc23469000.0d.00.00.7c.5f.00.00.00

To generate a template for an interface definition in the C syntax, enter:
/etc/ncs/uuid_gen -c

This produces the following output:
%c
[
uuid(34dc239ec000.0d.00.00.7c.5f.00.00.00),
version(1)
]
interface INTERFACENAME {

}

To generate a C source-code representation of a UUID, enter the following:
/etc/ncs/uuid_gen -C

This produces the following output:
= { 0x34dc23af,
0xf000,
0x0000,
0x0d,
{0x00, 0x00, 0x7c, 0x5f, 0x00, 0x00, 0x00} };

To generate a template for an interface definition in the Pascal syntax, enter the following:
/etc/ncs/uuid_gen -p

This produces the following output:
%pascal
[
uuid (458487b55160.02.c0.64.02.03.00.00.00),
version (1)
]
interface INTERFACENAME;

end;

To generate a Pascal source-code representation of a UUID, enter the following:
/etc/ncs/uuid_gen -P

This produces the following output:
:= [
time_high := 16#458487df,
time_low := 16#9fb2,
reserved := 16#000,
family := chr(16#02),
host := [chr(16#c0), chr(16#64), chr(16#02), chr(16#03),
chr(16#00), chr(16#00), chr(16#00)]