正则加递归去除指定的多个字符

Question

原字符串 String str="SUM(TA0047/(TA0012+TA0023+SUM((TA0034+TA0045))))"
程序处理过的字符串
String newStr="TA0047/(TA0012+TA0023+(TA0034+TA0045))"

目的就是去掉SUM() 或者AVG() 等等....

思路.....不清晰....求助

Answer 1

试一下这个

 public static void main(String[] args) {
        // 按指定模式在字符串查找
        String line = "SUM(TA0047/(TA0012+TA0023+SUM((TA0034+TA0045))))";
        String pattern = "(.*)?SUM\\((.*)\\)";

        // 创建 Pattern 对象
        Pattern r = Pattern.compile(pattern);

        // 现在创建 matcher 对象
        Matcher m = r.matcher(line);
        while (m.find()) {
            String s = null;
            try {
                //尝试获取第二个
                s = m.group(2);
                line = m.group(1) + m.group(2);
            } catch (Exception e) {
                //不存在第二个，则获取第一个
                s = m.group(1);
                line = m.group(1);
            }
            System.out.println("Found value: " + s);

            m = r.matcher(line);
        }

        System.out.println(line);
    }