在char与int的强行转换中遇到的问题？

Question

 #include<stdio.h>
#include<stdlib.h>
#include<string.h>

int main()
{
    int a, b;
    int i = 0;
    char s[80];
    scanf_s("%d %d", &a, &b);
    while (a / b != 0)
        a /= 10;
    for (int i = 0; i < 80; i++) {
        s[i] = (a * 10) / b+48;
        a = (a * 10) % b;
    }
    printf("%s", s);
    return 0;
}

不知道为什么，输出的结果无论字符串长度有多大，结尾总有四个“烫”，请问这是为什么？

Answer 1

烫 是因为没初始化 你改成下面试试

```int main()
{
int a=3, b=5;
int i = 0;
char s[80] = {'\0'};
scanf_s("%d %d", &a, &b);
while (a / b != 0)
a /= 10;
int l = sizeof(s) / sizeof(char*);
for (int i = 0; i < l; i++) {
int c = (a * 10) / b + 48;
sprintf(&s[i],"%d", (const char*)c);
a = (a * 10) % b;
}
printf("%s",s);
return 0;
}