你好杰米 2018-10-10 03:12 采纳率: 88.9%
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【Java】怎么比较两个字符串中的数字大小?

现在有这样两个字符串
String time1 = "07:18";
String time2 = "12:21";

            Java中不能用 time1 > time2 这种方法比较,但是我发现js可以

            请问java中如何满足这样的需求

            (ps: 判断两个     时:分    的大小关系)
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8条回答 默认 最新

  • CZ__ 2018-10-10 07:20
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    String time1 = "12:21";
    String time2 = "07:18";
    System.out.println(time1.compareTo(time2));//1
    
    time1 = "20:21";
    time2 = "01:18";
    System.out.println(time1.compareTo(time2));//2
    
    time1 = "14:21";
    time2 = "10:18";
    System.out.println(time1.compareTo(time2));//4
    
    time1 = "14:21";
    time2 = "23:18";
    System.out.println(time1.compareTo(time2));//-1
    
    time1 = "14:21";
    time2 = "14:21";
    System.out.println(time1.compareTo(time2));//0
    

    事实说明,time1.compareTo(time2)返回结果>0说明time1大;返回结果<0说明time2大;返回结果=0说明一样大。

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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