如何在 PHP 中获取(提取)文件扩展名？

Question

This is a question you can read everywhere on the web with various answers :

$ext = end(explode('.', $filename));
$ext = substr(strrchr($filename, '.'), 1);
$ext = substr($filename, strrpos($filename, '.') + 1);
$ext = preg_replace('/^.*\.([^.]+)$/D', '$1', $filename);

$exts = split("[/\\.]", $filename);
$n    = count($exts)-1;
$ext  = $exts[$n];

etc.

However, there is always "the best way" and it should be on Stack Overflow.

转载于:https://stackoverflow.com/questions/173868/how-to-getextract-a-file-extension-in-php

Answer 1

People from other scripting languages always think theirs is better because they have a built in function to do that and not PHP (I am looking at pythonistas right now :-)).

In fact, it does exist, but few people know it. Meet pathinfo():

$ext = pathinfo($filename, PATHINFO_EXTENSION);

This is fast and built-in. pathinfo() can give you other information, such as canonical path, depending on the constant you pass to it.

Remember that if you want to be able to deal with non ASCII characters, you need to set the locale first. E.G:

setlocale(LC_ALL,'en_US.UTF-8');

Also note this doesn't take in consideration the file content or mimetype, you only get the extension. But it's what you asked for.

Lastly, note that this works only for a file path, not a URL ressources path, which are covered using PARSE_URL.

Enjoy