在 Perl 中，我如何创建一个哈希，它的键来自给定的数组？

Question

Let's say I have an array, and I know I'm going to be doing a lot of "Does the array contain X?" checks. The efficient way to do this is to turn that array into a hash, where the keys are the array's elements, and then you can just say

if($hash{X}) { ... }

Is there an easy way to do this array-to-hash conversion? Ideally, it should be versatile enough to take an anonymous array and return an anonymous hash.

转载于:https://stackoverflow.com/questions/95820/in-perl-how-do-i-create-a-hash-whose-keys-come-from-a-given-array

Answer 1

%hash = map { $_ => 1 } @array;

It's not as short as the "@hash{@array} = ..." solutions, but those ones require the hash and array to already be defined somewhere else, whereas this one can take an anonymous array and return an anonymous hash.

What this does is take each element in the array and pair it up with a "1". When this list of (key, 1, key, 1, key 1) pairs get assigned to a hash, the odd-numbered ones become the hash's keys, and the even-numbered ones become the respective values.