如何用正则匹配headers?

想把这种headers(Host: www.baidu.com)匹配成为下面这种,奈何不熟悉正则,求大神帮忙
'Host': 'www.baidu.com',

2个回答

如果你是用python的话,可以

headers ="Host:www.baidu.com"
new=re.sub('(.*?):(.*)',lambda m:"\'"+m.group(1)+"\':\'"+m.group(2)+"\',",headers)
print(new)
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weixin_42296198 刚开始学习爬虫,多谢大侠鼎力相助
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PHP get_headers()报告的标头不同于CURL

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scrapy在settdings.py中已经设置好了DEFAULT_REQUEST_HEADERS,在发起请求的时候应该怎么写headers?

scrapy在settdings.py中已经设置好了DEFAULT_REQUEST_HEADERS,在发起请求的时候应该怎么写headers?

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jquery ajax的文档里没有headers参数,为什么可以直接在settings里面放headers参数?

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