Lotus@ 2009-03-25 09:10 采纳率: 100%
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在 window.location.hash-更改?

I am using Ajax and hash for navigation.

Is there a way to check if the window.location.hash changed like this?

http://example.com/blah#123 to http://example.com/blah#456

It works if I check it when the document loads.

But if I have #hash based navigation it doesn't work when I press the back button on the browser (so I jump from blah#456 to blah#123).

It shows inside the address box, but I can't catch it with JavaScript.

转载于:https://stackoverflow.com/questions/680785/on-window-location-hash-change

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  • ?yb? 2015-06-05 18:24
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    The only way to really do this (and is how the 'reallysimplehistory' does this), is by setting an interval that keeps checking the current hash, and comparing it against what it was before, we do this and let subscribers subscribe to a changed event that we fire if the hash changes.. its not perfect but browsers really don't support this event natively.


    Update to keep this answer fresh:

    If you are using jQuery (which today should be somewhat foundational for most) then a nice solution is to use the abstraction that jQuery gives you by using its events system to listen to hashchange events on the window object.

    $(window).on('hashchange', function() {
      //.. work ..
    });
    

    The nice thing here is you can write code that doesn't need to even worry about hashchange support, however you DO need to do some magic, in form of a somewhat lesser known jQuery feature jQuery special events.

    With this feature you essentially get to run some setup code for any event, the first time somebody attempts to use the event in any way (such as binding to the event).

    In this setup code you can check for native browser support and if the browser doesn't natively implement this, you can setup a single timer to poll for changes, and trigger the jQuery event.

    This completely unbinds your code from needing to understand this support problem, the implementation of a special event of this kind is trivial (to get a simple 98% working version), but why do that when somebody else has already.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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