胖鸭 2013-05-09 16:13
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在 Golang,有没有办法每隔一段时间做重复性的工作?

Is there a way to do repetitive background tasks in Go? I'm thinking of something like Timer.schedule(task, delay, period) in Java. I know I can do this with a goroutine and Time.sleep(), but I'd like something that easily stopped.

Here's what I got, but looks ugly to me. Is there a cleaner/better way?

func oneWay() {
    var f func()
    var t *time.Timer

    f = func () {
        fmt.Println("doing stuff")
        t = time.AfterFunc(time.Duration(5) * time.Second, f)
    }

    t = time.AfterFunc(time.Duration(5) * time.Second, f)

    defer t.Stop()

    //simulate doing stuff
    time.Sleep(time.Minute)
}

转载于:https://stackoverflow.com/questions/16466320/is-there-a-way-to-do-repetitive-tasks-at-intervals-in-golang

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  • ℙℕℤℝ 2013-05-09 16:28
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    The function time.NewTicker makes a channel that sends a periodic message, and provides a way to stop it. Use it something like this (untested):

    ticker := time.NewTicker(5 * time.Second)
    quit := make(chan struct{})
    go func() {
        for {
           select {
            case <- ticker.C:
                // do stuff
            case <- quit:
                ticker.Stop()
                return
            }
        }
     }()
    

    You can stop the worker by closing the quit channel: close(quit).

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