python3.7爬虫 使用 selector.xpath('')爬取-线上等

Question

我想用正则取以下的

            LANEIGE (兰芝) Deep Pore Cleansing Foam

            字串即可，请用我用python   selector.xpath('') 的语法要怎么写呢

            '''''''''''''''''''''''''''''''''''''''''''''''
            <div class="col-md-10" >
        <div style="margin:10px 0px; float:left;width:100%;">

            <div style="float:left;margin-left:10px;margin-top:20px;">
                <p> 
                    <span class="fullName">LANEIGE (兰芝) Deep Pore Cleansing Foam</span>

                    <span class="certificate">

                    </span>
                </p>

                <p class="member">

                    <span class="createDttm">
                        更新于:&nbsp;2018-12-02

                        ，&nbsp;资料来源: 其他(非官方)网站

                    </span>
                </p>
            </div>


        </div>
        ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
        www.cosgua.com/cosmetic/1000(原网址)

Answer 1

from scrapy.selector import Selector

 html='''
            <div class="col-md-10" >
        <div style="margin:10px 0px; float:left;width:100%;">

            <div style="float:left;margin-left:10px;margin-top:20px;">
                <p> 
                    <span class="fullName">LANEIGE (兰芝) Deep Pore Cleansing Foam</span>

                    <span class="certificate">

                    </span>
                </p>

                <p class="member">

                    <span class="createDttm">
                        更新于:&nbsp;2018-12-02

                        ，&nbsp;资料来源: 其他(非官方)网站

                    </span>
                </p>
            </div>


        </div>
'''
selector = Selector(text=html)
txt=selector.xpath('//div/p/span[@class="fullName"]/text()').extract_first()
print(txt)