杭电OJ数组越界Runtime Error (ACCESS_VIOLATION)
#include<algorithm>
#define NN 1005
#define INF 0x3f3f3f3f
using namespace std;
int n,k,m,i,j,a,b,c,d[NN][NN],w[NN][NN],u,flag,sum;
struct edge
{
    int u;
    int v;
    int id;
} ed[NN];

int main()
{

    while(scanf("%d%d",&n,&m)!=EOF)
    {

        for(i=1; i<=m; i++)
        {
            scanf("%d%d",&a,&b);
            ed[i].u=a;
            ed[i].v=b;
            ed[i].id=i;

        }//输入完毕

        for(i=1; i<=m; i++)
        {
             flag=0;
             sum=0;
            for(k=1; k<=n; k++)
            {
                for(j=1; j<=n; j++)
                {
                    w[k][j]=INF;
                    d[k][j]=INF;
                }
            }
            for(j=1; j<=m; j++)
            {
                if(j!=i)
                {
                    a=ed[j].u;
                    b=ed[j].v;
                    w[a][b]=w[b][a]=1;//第x条路被封

                }
            }
            d[1][1]=0;
            for(u=1; u<=n; u++)
                for(k=1; k<=n; k++)
                    for(j=1; j<=n; j++)
                    {


                        d[k][j]=min(d[k][j],d[k][u]+w[u][j]);

                        if(k==j)
                            d[k][j]=0;


                    }
            for(k=1; k<=n; k++)
                for(j=1; j<=n; j++)
                    if((d[k][j]!=INF)&&(!flag))
                    {
                        sum+=d[k][j];

                    }
                    else
                    {

                        flag=1;
                    }
            if(!flag)
                printf("%d\n",sum);
                else
                    printf("INF\n");
        }
    }
}


hdu 2433
http://acm.hdu.edu.cn/showproblem.php?pid=2433
用测试结果没问题,但提交就是
Runtime Error (ACCESS_VIOLATION)
qiu'jie'da

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oj新人求指点[img=https://forum.csdn.net/PointForum/ui/scripts/csdn/Plugin/003/monkey/2.gif][/img]rn在本机上的vc6.0跑了给的测试用例,能通过,但提交到oj上就runtime error,是在想不通哪里有问题[img=https://forum.csdn.net/PointForum/ui/scripts/csdn/Plugin/001/face/9.gif][/img],请大佬们指点。rnrn下面是我runtime error的代码rn[code=c]#includern#includern#includernrnint main()rnrn int day,m;rn scanf("%d",&day);rn if(day==0) return 0;rn while(day)rn rn scanf("%d",&m);rnrn int on,on1,on2,on3;rn int off,off1,off2,off3;rn int first=1;rn char num[15],ear_num[15],late_num[15];rn int ear=86399,late=0;rnrn while(m)rn rn scanf("%s",num);rn scanf("%d:%d:%d",&on1,&on2,&on3);rn scanf("%d:%d:%d",&off1,&off2,&off3);rnrn if(m==1 && first==1)rn strcpy(ear_num,num);rn strcpy(late_num,num);rn break;rn rn rn on=on1*3600+on2*60+on3;rn off=off1*3600+off2*60+off3;rn rn if(on<=ear)rn ear=on;rn strcpy(ear_num,num); rn rnrn if(off>=late)rn late=off;rn strcpy(late_num,num);rn rnrn first=0;rn m--;rn rn printf("%s %s\n",ear_num,late_num);rn day--;rn rn return 0;rn[/code]rnrn原题是:rnrn题目描述:rn 每天第一个到机房的人要把门打开,最后一个离开的人要把门关好。现有一堆杂乱的机房签到、签离记录,请根据记录找出当天开门和关门的人。rnrn输入:rnrn 测试输入的第一行给出记录的总天数N ( N> 0 ),下面列出了N天的记录。rn 每天的记录在第一行给出记录的条目数M (M > 0 ),下面是M行,每行的格式为rnrn 证件号码 签到时间 签离时间rnrn 其中时间按“小时:分钟:秒钟”(各占2位)给出,证件号码是长度不超过15的字符串。rnrn输出:rnrn 对每一天的记录输出1行,即当天开门和关门人的证件号码,中间用1空格分隔。rn 注意:在裁判的标准测试输入中,所有记录保证完整,每个人的签到时间在签离时间之前,且没有多人同时签到或者签离的情况。rnrn样例输入:rnrn 3rn 1rn ME3021112225321 00:00:00 23:59:59rn 2rn EE301218 08:05:35 20:56:35rn MA301134 12:35:45 21:40:42rn 3rn CS301111 15:30:28 17:00:10rn SC3021234 08:00:00 11:25:25rn CS301133 21:45:00 21:58:40rnrn样例输出:rnrn ME3021112225321 ME3021112225321rn EE301218 MA301134rn SC3021234 CS301133rnrn
Runtime Error (ACCESS_VIOLATION)是什么错误啊?求大神帮助啊!
hdoj1107rnrn#includernusing namespace std;rnint a[13][13][1000],ma[3],jilu,n;rnstruct funrnrn char name;rn int x,y;rn int neili,wuyi,shengmingli;rn int direction;//0的话为最还是得方向rnt[1000];rnint fun1(int i)//参数为t结构体的下标rnrn float q;rn q=(0.5*t[i].neili+0.5*t[i].wuyi)*(t[i].shengmingli+10)*1.0/100;rn return static_cast(q);rnrnint fun2(int i)rnrn float q;rn q=(0.8*t[i].neili+0.2*t[i].wuyi)*(t[i].shengmingli+10)*1.0/100;rn return static_cast(q);rnrnint fun3(int i)rnrn float q;rn q=(0.2*t[i].neili+0.2*t[i].wuyi)*(t[i].shengmingli+10)*1.0/100;rn return static_cast(q);rnrnvoid zhandou()rn for(int i=1;i<=12;i++)rn rn for(int j=1;j<=12;j++)rn rn if((a[i][j][0]==2)&&(t[a[i][j][1]].name!=t[a[i][j][2]].name)&&t[a[i][j][1]].shengmingli>0&&t[a[i][j][2]].shengmingli>0)//判断是两个人并且是是不同派的rn rn for(int k=1;k<=2;k++)rn rn if(t[a[i][j][k]].name=='S')//分别算出攻击力rn ma[k]=fun1(a[i][j][k]);//返回的是攻击力rn if(t[a[i][j][k]].name=='W')rn ma[k]=fun2(a[i][j][k]);rn if(t[a[i][j][k]].name=='E')rn ma[k]=fun3(a[i][j][k]);rn rn t[a[i][j][1]].shengmingli-=ma[2];//算出战斗后的生命力的rn t[a[i][j][2]].shengmingli-=ma[1];rn rn rn rnrnvoid funs(int i)rnrn int m;rn m=t[i].x;rn if(t[i].direction==0)//判读向下走rn rn if(t[i].x<12)rn rn a[t[i].x][t[i].y][0]--;rn t[i].x++;rn a[t[i].x][t[i].y][0]++;rn rn elsern rn t[i].direction=1;rn a[t[i].x][t[i].y][0]--;rn t[i].x--;rn a[t[i].x][t[i].y][0]++;rn rn rn elsern rn if(t[i].x>1)rn rn a[t[i].x][t[i].y][0]--;rn t[i].x--;rn a[t[i].x][t[i].y][0]++;rn rn elsern rn t[i].direction=0;rn a[t[i].x][t[i].y][0]--;rn t[i].x++;rn a[t[i].x][t[i].y][0]++;rn rn rn int k=1;rn int w=1;rn while(a[t[i].x][t[i].y][w]!=0)rn w++;rn while(a[m][t[i].y][k]!=0)rn rn rn a[t[i].x][t[i].y][w]=a[m][t[i].y][k];rn a[m][t[i].y][k]=0;rn k++;rn w++;rn rnrnvoid funw(int i)rnrn int m=t[i].y;rn if(t[i].direction==0)rn rn if(t[i].y<12)rn rn a[t[i].x][t[i].y][0]--;rn t[i].y++;rn a[t[i].x][t[i].y][0]++;rn rn elsern rn t[i].direction=1;rn a[t[i].x][t[i].y][0]--;rn t[i].y--;rn a[t[i].x][t[i].y][0]++;rn rn rn elsern rn if(t[i].y>1)rn rn a[t[i].x][t[i].y][0]--;rn t[i].y--;rn a[t[i].x][t[i].y][0]++;rn rn elsern rn t[i].direction=0;rn a[t[i].x][t[i].y][0]--;rn t[i].y++;rn a[t[i].x][t[i].y][0]++;rn rn rn int k=1;rn int w=1;rn while(a[t[i].x][t[i].y][w]!=0)rn w++;rn while(a[t[i].x][m][k]!=0)rn rn a[t[i].x][t[i].y][w]=a[t[i].x][m][k];rn a[t[i].x][m][k]=0;rn k++;rn w++;rn rnrnvoid fune(int i)rnrn int m1=t[i].x,m2=t[i].y;rn if(t[i].direction==0)rn rn if((t[i].x<12)&&(t[i].y)<12)rn rn a[t[i].x][t[i].y][0]--;rn t[i].x++;rn t[i].y++;rn a[t[i].x][t[i].y][0]++;rn rn else if((t[i].x>1)&&(t[i].y>1))rn rn t[i].direction=1;rn a[t[i].x][t[i].y][0]--;rn t[i].x--;rn t[i].y--;rn a[t[i].x][t[i].y][0]++;rn rn rn elsern rn if((t[i].x>1)&&(t[i].y>1))rn rn a[t[i].x][t[i].y][0]--;rn t[i].x--;rn t[i].y--;rn a[t[i].x][t[i].y][0]++;rn rn else if((t[i].x<12)&&(t[i].y)<12)rn rn t[i].direction=0;rn a[t[i].x][t[i].y][0]--;rn t[i].x++;rn t[i].y++;rn a[t[i].x][t[i].y][0]++;rn rn rn int k=1;rn int w=1;rn while(a[t[i].x][t[i].y][w]!=0)rn w++;rn while(a[m1][m2][k]!=0)rn rn a[t[i].x][t[i].y][w]=a[m1][m2][k];rn a[m1][m2][k]=0;rn k++;rn w++;rn rnrnint main()rnrn int T;rn cin>>T;rn while(T--)rn rn jilu=0;//记录t结构体的下标rn cin>>n;rn memset(a,0,sizeof(a));rn int i=1;rn while(cin>>t[i].name)//对数据进行输入rn rn if(t[i].name=='0')rn break;rn jilu++;//记录人数的rn cin>>t[i].x>>t[i].y>>t[i].neili>>t[i].wuyi>>t[i].shengmingli;rn a[t[i].x][t[i].y][0]++;//记录所在的坐标rn t[i].direction=0;//记录方向rn int k=1;//记录本人的信息是在某个坐标记录的rn while(a[t[i].x][t[i].y][k]!=0)rn k++;rn a[t[i].x][t[i].y][k]=i;rn i++;rn rn rn for(int l=1;l<=n;l++)//每次走一步的rn rn zhandou();//将战斗进行一次rn for(i=1;i<=jilu;i++)//分别让他们走路的rn rn if(t[i].shengmingli<=0)rn continue;rn if(t[i].name=='S')//提供的是结构体的下标rn funs(i);//走路的函数 rn if(t[i].name=='W')rn funw(i);rn if(t[i].name=='E')rn fune(i); rn rn rn rn int max1=0,max2=0,max3=0,max4=0,max5=0,max6=0;rn for(i=1;i<=jilu;i++)rn rn if(t[i].name=='S'&&t[i].shengmingli>0)rn rn max1++;rn max2+=t[i].shengmingli;rn continue;rn rn if(t[i].name=='W'&&t[i].shengmingli>0)rn rn max3++;rn max4+=t[i].shengmingli;rn continue;rn rn if(t[i].name=='E'&&t[i].shengmingli>0)rn rn max5++;rn max6+=t[i].shengmingli;rn continue;rn rn rn cout<
越界问题,一个问题出现了Runtime Error (ACCESS_VIOLATION)
不值得哪儿越界了,求大神看看[code=c]/*rnHDU 1102 Constructing Roadsrn题意:有n个乡村,修路,然后保证每两条路之间连接。rn如果A和B连接,那么A和B直接连接或者中间还有一个乡村,间接连接。rn已经有一些路了,你的任务是找出来一路径连接所有乡村。rn输入:i到j的长度,注意去重边rn最小生成树,,,rn*/rn#includern#includern#includern#includernusing namespace std;rnrnconst int N = 10005;rnstruct edgernrn int u,v,w;rne[N];rnint n,f[N];rn//将边降序排序rnbool cmp(edge a,edge b)rnrn return a.w<=b.w;rnrnvoid Init()rnrn for(int i = 1;i <= n;i++)rn f[i] = i;rnrnrnint getf(int u)rnrn if(f[u] == u)rn return u;rn elsern rn f[u] = getf(f[u]);rn return f[u];rn rnrnvoid merge(int u,int v)rnrn int t1 = getf(u);rn int t2 = getf(v);rn if(t1 != t2)rn rn f[t2] = t1;rn rnrnint Kruskal(int m)rnrn int ans=0;rn sort(e,e+m+1,cmp);rn for(int i=1;i<=m;i++)rn rn if(getf(e[i].u)!=getf(e[i].v))//未连通rn rn merge(e[i].u,e[i].v);rn ans+=e[i].w;rn rn rn return ans;rnrnint main()rnrn while(~scanf("%d",&n))rn rn memset(e,0,sizeof(e));rn int x,num = 1;rn for(int i = 1;i <= n;i++)rn for(int j = 1;j <= n;j++)rn rn scanf("%d",&x);rn if(i >= j)rn continue;rn e[num].u = i;rn e[num].v = j;rn e[num].w = x;rn num++;rn rnrn Init();//并查集优化rnrn int q,t1,t2;rn scanf("%d",&q);rn for(int i = 0;i < q;i++)rn rn scanf("%d%d",&t1,&t2);rn merge(t1,t2);//合并已有的道路rn rn printf("%d\n",Kruskal(num-1));rn rn return 0;rnrn/*rn3rn0 990 692rn990 0 179rn692 179 0rn1rn1 2rn*/rn[/code]
杭电ACM 1022 感觉是小改动 却出现Runtime Error(ACCESS_VIOLATION) 请各位帮我看看
请问各位 为什么这样写能AC 但是...rn[code=C/C++]rn#includernusing namespace std;rnrnint main()rnrn int n;rn while(cin>>n)rn rn if(n>9)rn rn cout<<"输入错误,请重新输入"<>order1>>order2;rn int length,i,j;rn for(i=0,j=0,length=0;i!=n;)rn rn if(length==0||stack[length-1]!=order2[j])//这里...rn rn stack[length++]=order1[i++];rn rn for(;length>0&&stack[length-1]==order2[j];)rn rn --length;rn ++j;rn rn rn if(length==0)rn rn cout<<"Yes."<0&&stack[length-1]==order2[j];)rn rn --length;rn ++j;rn cout<<"out"<rnusing namespace std;rnrnint main()rnrn int n;rn while(cin>>n)rn rn if(n>9)rn rn cout<<"输入错误,请重新输入"<>order1>>order2;rn int length,i,j;rn for(i=0,j=0,length=0;i!=n;)rn rn for(;length==0||stack[length-1]!=order2[j];)//和这里... rn stack[length++]=order1[i++];rn rn for(;length>0&&stack[length-1]==order2[j];)rn rn --length;rn ++j;rn rn rn if(length==0)rn rn cout<<"Yes."<0&&stack[length-1]==order2[j];)rn rn --length;rn ++j;rn cout<<"out"<
做acm题,出现Runtime Error(ACCESS_VIOLATION),怎么解决呀?
rn这是题目 http://acm.tzc.edu.cn/acmhome/problemdetail.do?&method=showdetail&id=1055rn#include rnusing namespace std;rnint main()rnrn char a[101];rn int i,j=0;rn while(cin>>a[j])rn rn j++;rn rn cout<=65 && a[i]<90) a[i]+=33;rn if(a[i]==90) a[i]='a';rn rn a[j]='\0';rn cout<
程序运行结果提示“Runtime Error(ACCESS_VIOLATION)”,该怎样修改?
小女子编程能力不太好,在此烦请各位大侠帮帮忙啦!rnrnrn/***********************************************************************************************rn****从n个数中,暗中从大到小的顺序输出前m大的数,其中每组测试数据有两行,第一行有两个数n,m*******rn****(0rn#define M 100000rnrnint sort(int r[],int low,int high) //快速排序函数,使数组按照由大到小的顺序排列rn int i=low,j=high;rn int pivot=r[low];rn if(i>j)rn return 0;rn while(i=pivot)rn i++;rn r[j]=r[i];rn rn r[i]=pivot;rn sort(r,low,i-1); rn sort(r,i+1,high);rn return 1;rn rnrnvoid main()rn// freopen("shuru.txt","r",stdin);rn int i,n,m;rn int r[M];rn while(scanf("%d%d\n",&n,&m)!=EOF) //输入n和m的值rn for(i=0;i
ACM hdu1558 Runtime Error (ACCESS_VIOLATION) 不明白哪里导致这个错误
题目就是并查集加线段相交判断,但一直Runtime Error (ACCESS_VIOLATION),数组大小应该没错,求解释rn[code=C/C++]#includernusing namespace std;rndouble max ( double x1, double x2 ) return x1>x2?x1:x2; rndouble min ( double x1, double x2 ) return x1= min(s2.x, e2.x)) &&rn (max(s2.x, e2.x) >= min(s1.x, e1.x)) &&rn (max(s1.y, e1.y) >= min(s2.y, e2.y)) &&rn (max(s2.y, e2.y) >= min(s1.y, e1.y)) &&rn (xmult(s2, e1, s1) * xmult(e1, e2, s1) >= 0) &&rn (xmult(s1, e2, s2) * xmult(e2, e1, s2) >= 0)rn ) rn return true;rn return false; rnrnrnvoid UFset( ) rnrn int i;rn for( i=1; i<=1001; i++ ) rn parent[i] = -1;rnrnrnint Find( int x ) rnrn int s; rn for( s=x; parent[s]>=0; s=parent[s] )rn ;rn while( s!=x ) rn rn int tmp = parent[x];rn parent[x] = s;rn x = tmp;rn rn return s;rnrnrnvoid Union( int R1, int R2 )rnrn int r1 = Find(R1), r2 = Find(R2); rn int tmp = parent[r1] + parent[r2]; rn if( parent[r1] > parent[r2] ) rn rn parent[r1] = r2; rn parent[r2] = tmp;rn rn elsern rn parent[r2] = r1; rn parent[r1] = tmp;rn rnrnint main()rnrn int test, n, i, j, id;rn char order;rn cin>>test;rn while(test--)rn rn i=1;rn cin>>n;rn UFset();rn while(n--)rn rn cin>>order;rn if(order=='P')rn rn cin>>seg[i].s.x>>seg[i].s.y>>seg[i].e.x>>seg[i].e.y;rn for(j=i-1; j>=1; j--)rn if(isIntersected(seg[j].s, seg[j].e, seg[i].s, seg[i].e))rn Union(j, i);rn i++;rn rn elsern rn cin>>id;rn cout<<-parent[Find(id)]<
求大神解答:Runtime Error(ACCESS_VIOLATION)是个什么错误?
在杭电oj上做到了一个线段树的问题,但当时我并不是很懂线段数,所以就尝试了其他方法,只用了数组,结果运行之后的答案是对的,submit之后却显示了Runtime Error(ACCESS_VIOLATION),求大神解答。
杭电2034题 提交的时候出现的Runtime Error (ACCESS_VIOLATION) 各位大佬给小弟看看,谢谢。。
#include rnint main()rnrn int m,n;rn while(scanf("%d%d",&n,&m)!=EOF)rn rn if(n>0&&n<=100&&m>0&&m<=100)rn rn int i,j,a[100],b[100],count=0;rn for(i=0;i
OJ上的题目Runtime error(SIGSEGV)
[code=c]#includern#includern#includernint main()rnrn char a[10000];rn int i,j,n,l,u,b[100]=0;rn for(i=0,n=0;(fgets(a,100000,stdin))!=NULL;i++)rn rn if(a[strlen(a)-1]=='\n')rn a[strlen(a)-1]='\0';rn l=0;rn u=0;rn for(j=0;j0&&u==-1)rn b[n++]=l;rn else if(u>0&&l==-1)rn b[n++]=u;rn elsern b[n++]=-1;rn rn for(i=0;i
在OJ上运行时出现Runtime Error错误
在自己的编译器上是可以运行成功的,但是在九度OJ上提交时,就会出现Runtime Error错误~rnrnrn题目描述:rn输入一个数组的值,求出各个值从小到大排序后的次序。rn输入:rn输入有多组数据。rn每组输入的第一个数为数组的长度n(1<=n<=10000),后面的数为数组中的值,以空格分割。rn输出:rn各输入的值按从小到大排列的次序(最后一个数字后面没有空格)。rn样例输入:rn4rn-3 75 12 -3rn样例输出:rn1 3 2 1rn来源:rn2009年北京航空航天大学计算机研究生机试真题rnrn#include rnint main()rn int x,n,a[100],b[100];rn//输入数组rn while(scanf("%d",&n)!=EOF)rn for(int i=0;ia[j])rn int p=a[i];rn a[i]=a[j];rn a[j]=p;rn rn rn rn//数组去除重复数字rn int count=n;rn for(int i=0;i
杭电OJ
输入一行数字,如果我们把这行数字中的‘5’都看成空格,那么就得到一行用空格分割的若干非负整数(可能有些整数以‘0’开头,这些头部的‘0’应该被忽略掉,除非这个整数就是由若干个‘0’组成的,这时这个整数就是0)。 你的任务是:对这些分割得到的整数,依从小到大的顺序排序输出。 Input 输入包含多组测试用例,每组输入数据只有一行数字(数字之间没有空格),这行数字的长度不大于1000。 输入数据
杭电OJ上面提示Compilation Error
http://acm.hdu.edu.cn/showproblem.php?pid=2071rn水题。还有另外一道,也是提示那个。rn代码rn[code=C/C++]rn#includernint main()rnrn int cnt;rn scanf("%d",&cnt);rn for(int i=0;in?m:n;rn rn printf("%.2lf\n",m);rn rnrnrn[/code]
杭电oj
Problem Title 2  Pro. ID 1001 Sum Problem #include&amp;lt;stdio.h&amp;gt; int main() { int i,n,sum=0; while(scanf(&quot;%d&quot;,&amp;amp;n)!=EOF){ sum=0; for(i=1;i&amp;lt;=n;i++){ sum = ...
ACCESS_VIOLATION
#includernint a[5000000];rnint main()rnrn int i,j,t,n,x;rn while(scanf("%d",&n)!=EOF)rn rn getchar();rn for(i=0;i
Runtime error
一早起来,编译,运行VC,结果出现这种错误rnvc runtime error this application has requested the runtime to terminate it in an unusual wayrn请问一下,这个问题该如何解决啊?
runtime error
我在调试程序的时候突然出现一个runtime error的错误,错误框的标题是rnMicroSoft Visual C++ Libraryrnrn内容是:rnruntime error!rnprogram:我的程序名rnabnormal program terminationrnrn大家帮助看看可能是什么原因造成的?
Runtime error!
VC++ 程序运行后,用了很长时间也没发现问题。最近有时会突然出现一个错误的提示框(极少出现)。rnrnRuntime Error!rnrnprogram: c:\documents and settings\.....rnrnThis application has requested the Runtime to terminate it in an unusual way. Pleasse contact the application'support team for more information.rnrnrn感觉好像是本生操作系统的问题导致的。。请教各位,帮忙分析下。谢谢!rn
Runtime Error
捕捉了,但还是不行,我加上了delete datamanage 后,不会出现Runtime Error,但会出现内存不能读的问题.
runtime error?
用vc做的一个程序,运行一段时间老出现runtime error错误?rn那位可以解释一下runtime 到底是什么东西rn出现错误的原因是什么???
RunTime Error!
在我机器上运行没有问题,可是一放到服务器上就出现这样的错误,头疼。rn又无法在服务器上进行调试,我该怎么做。
Runtime Error!
rn rnMFC程序Release版本,在一些机器可以正常运行,rn但是在我同事一台XP系统上一运行就跳出这个提示:rnRuntime Error!rnrnProgram:D:\bin\OfficeBank.exernrnthis application has requested the Runtime to terminate it in an unusual way Please contact the application's support team for more information.rnrn 确定rnrn我用depends在那台机器看过,不缺少动态库文件。请教大侠们,怎么办?
runtime ERROR
runtime error rnprogram:c:\program files\internet explore\iexplore.exe rnrn这是全部对话框文字 rn点了下面的确定后,页面就关闭了,每次都是,不点确定也点不了页面。 rn不知道怎么办 rn请各位大侠出手相助,感激涕零啊! rnrn下面的那位大侠,能说仔细点吗? rn实在是 不明白啊rn
Runtime error?
Runtime Error rnDescription: An application error occurred on the server. The current custom error settings for this application prevent the details of the application error from being viewed remotely (for security reasons). It could, however, be viewed by browsers running on the local server machine. rnrnDetails: To enable the details of this specific error message to be viewable on remote machines, please create a tag within a "web.config" configuration file located in the root directory of the current web application. This tag should then have its "mode" attribute set to "Off".rnrnrnrnrnrn rn rn rnrn rnrnNotes: The current error page you are seeing can be replaced by a custom error page by modifying the "defaultRedirect" attribute of the application's configuration tag to point to a custom error page URL.rnrnrnrnrnrn rn rn rnrn rn在自己电脑上是可以的换了台服务期就出现了这样的错误,看了前面的贴子,解决不了问题rn急用!要部署到服务器上,可就是这个错!!!!!!!!!
RunTime Error
开发工具:[color=#FF0000]VS2005 + SQL2005[/color]rnrn以下环境运行OKrn[color=#FF0000]SQL2005rnServer2003[/color]rnrnrn以下环境出现 RunTime Errorrn[color=#FF0000]SQL2008rnServer2008[/color]rnrnrn错误发生举例:rn页面Insert时,用户没有继续等待直接换页面(SELECT)rnServer2003 + SQL2005以上操作没问题。rnServer2008 + SQL2008就会出现。。。。。。。。rnrn处理方法:rnINSERT,UPDATE 语句+锁:[code=SQL]with(Tablock)[/code]rn但据客户反问题还是存在。。。。。。。。。。。。rnrn因自己公司没有Server2008 和 SQL2008所以没法调试。。。而客户那边是不允许外来人员加入或的(AD登陆系统),所以也没法调试。。。。。rnrn特来请教
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