#include <stdio.h>
int main ()
{
   int n, i, j, k, p, q, t, u, length;
   int a[100];
   int diff[100];

   scanf ("%d", &n);

       for (i = 0; i < n; i++)
       {
           scanf ("%d", &a[i]);
       }                                        //输入一个长度为n的数组


       for (j = 0; j < n; j++)
       {
           if (a[j] > a[j+1])
           {
               t = a[j];
               a[j] = a[j+1];
               a[j+1] = t;
           }
       }                                       //按从小到大顺序排列



       for (k = 0; k < n - 1; k++)
       {
           diff[k] = a[k+1] - a[k];
       }                                      //diff[k]相邻两项的差组成的一个新数组


    for (p = 0; p < n - 1; p++)
    {
       if (diff[p] > diff[p+1])
       {
           u = diff[p];
           diff[p] = diff [p+1];
           diff[p+1] = u;
       }
   }                                         //按从小到大顺序排列数组diff[p]


    for (q = 0, length = 0; diff[q] == 0||1; q++)
    {
       length++;
    }                                         //若diff[q]==0或1，说明连续，即length+1

   printf ("%d", length);                    //输出length
   return 0;
}

java.net.SocketTimeoutException: Read timed out ？？？

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