请教各位大神，我的程序执行的时候无法终止？

Question

请教各位大神，我的程序执行的时候无法终止，case1和3有这个问题，用断点看了半天没看懂，用loop ，goto loop 的方法也试过，没有解决问题。请教。

#include <iostream>
#include <string>
#include <stdlib.h>
#include <stdio.h>
#include <iomanip>
using namespace std;

typedef int ElemType;
struct Addressbook
{
    ElemType data;
    Addressbook *next;
};

class LinkList 
{
private :
    Addressbook *Head;
public:
    LinkList ();
    ~LinkList(){}
    void Creat (int n);
    void Display();
    void Insert (int i,ElemType e);
    void Delete(int i);
};

LinkList::LinkList()
{
    Head=new Addressbook;
    Head->next=NULL;
}

void LinkList::Creat(int n)
{
    int i,length;
    Addressbook *p,*q;
    length=n;
    if(length>0)
    {
        cout<<"Input data elem:";
        for(i=1;i<=length;i++)
        {
            p=new Addressbook;
            cin>>p->data;
            p->next=NULL;
            if(i==1)
                Head->next=p;
            else
                q->next=p;
            q=p;
        }
    }
    else 
        cout<<"Length Error!"<<endl;
}

void LinkList::Display()
{   
    Addressbook *p;
    p=Head->next;
    if(p==NULL)
        cout<<"LinkList Is Empty!"<<endl;
    else
    {
        cout<<"Data Elem:";
        while(p!=NULL)
        {
            cout<<"通讯录人数"<<endl;
            cout<<"姓名 性别 住址 电话号码"<<endl;
            cout<<setw(20)<<p->data;
            p=p->next;
        }
    }
    cout<<endl;
}

void LinkList::Insert (int i,ElemType e)
{
    Addressbook *p,*q,*s;
    int k=1;
    q=Head;
    p=Head->next;
    while(k<i&&p!=NULL)
    {
        q=p;
        p=p->next;
        k++;
    }
    if (k==i)
    {
        s=new Addressbook;
        s->data=e;  
        s->next=p;
        q->next=s;
        cout<<"Insert Success!"<<endl;
    }
    else
        cout<<"Insert Location i Error!"<<endl;
}

void LinkList::Delete(int i)
{
    Addressbook *p,*q;
    int k=1;
    q=Head;
    p=Head->next;
    while(k<i&&p!=NULL)
    {
        q=p;
        p=p->next;
        k++;
    }
    if(k==i)
    {
        q->next=p->next;
        delete p;
        cout<<"已删除通讯录信息"<<endl;

    }
    else
    {
        cout <<"Delete Location Error!"<<endl;
    }
}

void main()
{
    int i,n,choice=0;
    ElemType e;
    LinkList ll;
    do
    {   
        cout<<"************************************"<<endl;
        cout<<"***********通讯录信息管理系统*******"<<endl;
        cout<<"***************1建立****************"<<endl;
        cout<<"***************2查询****************"<<endl;
        cout<<"***************3插入****************"<<endl;
        cout<<"***************4删除****************"<<endl;
        cout<<"***************0退出****************"<<endl;
        cout<<"************************************"<<endl;
        cout<<"请选择0-4";
        cin>>choice;
        switch(choice)
        {
        case 1:
            {
                cout<<"请输入人数";
                cin>>n;
                ll.Creat(n);
                break;
                /*goto loop;*/
            }
        loop:case 2:
            {
                ll.Display();
                break;
            }
        case 3:
            {
                cout<<"请输入要插入位置";
                cin>>i;
                cout<<"请输入要插入的通讯录信息逗号隔开"<<endl;
                cout<<"姓名，性别，住址，电话号码"<<endl;
                cin>>e;
                ll.Insert(i,e);
                break;
                /*goto loop;*/
            }
        case 4:
            {
                cout<<"请输入要删除的位置";
                cin>>i;
                ll.Delete(i);
                break;
            }
        case 0:break;
        default:cout<<"请输入正确数字"<<endl;
        }
    }while(choice);
}

Answer 1

问老师以后弄清楚了。

typedef int ElemType;
struct Addressbook
{
    ElemType data;
    Addressbook *next;
};

以及阅读主函数和creat函数

void LinkList::Creat(int n)
{
  .......
    if(length>0)
    {
        cout<<"Input data elem:";

说明data 类型应该是char而不是定义为int，总之把typedef int改为typedef char 即可正确运行。