提示不存在从 " " 到 " *" 的适当转换函数，应该怎么解决？

Question

#include
typedef struct
{
char xing[15];
int sheng;
char ma[20];

}ren;
void Change( ren * a, ren * b)
{
ren cl;
cl = *a;
*a = *b;
*b = cl;
}
int main()
{
int a, b, d, e;
ren c[20];
scanf("%d", &a);
for (b = 0; b < a; b++)
{

    scanf("%s", c[b].xing);
    scanf("%d", &c[b].sheng);
    scanf("%s", c[b].ma);

}
/*3
    zhang 19850403 13912345678
    wang 19821020 + 86 - 0571 - 88018448
    qian 19840619 13609876543*/
/*for (b = a-1; b < a; b++)
{

    printf("%s", c[b].xing);
    printf("%d", c[b].sheng);
    printf("%s", c[b].ma);
    printf("\n");
}*/
e = c[0].sheng;
for (b = 0; b < a - 1; b++)
{
    for (d = 0; d < a-b-1; d++)
    {
        if (c[d].sheng > c[d + 1].sheng)
        {
            Change(c[d], c[d + 1]);
        }
    }
}
for (b = 0; b < a; b++)
{
    printf("%s ", c[b].xing);
    printf("%d ", c[b].sheng);
    printf("%s\n", c[b].ma);
}
return 0;

}

Answer 1

Change(c[d], c[d + 1])改为Change(&c[d], &c[d + 1]);