如何将SELECT改用LINK_TO

Question

[code] function loadItemByCatalog(id)
{
var src = $('category');
var selected = src.selectedIndex;
$('cat').innerHTML= src.options[selected].innerHTML;

    //下面是請求的地址
    var url = "/auctioning/list_items" ;
    var params = "kind=" + id;
    //創建一個Ajax.Request對象，對應於發送一次Ajax請求
    var myAjax = new Ajax.Request(
    url,
    {       
    //請求方式：POST
    method:'post',
    //設置請求參數
    parameters: params,
    //指定回調函數
    onComplete: showList,
    //是否異步發送請求
    asynchronous:true
    }); 
}
    <select id="category" name="category" size="8" onChange="loadItemByCatalog(this.value);">        
            <%= options_from_collection_for_select(@categories, "id", "cname") %>        
        </select>[/code]

[b]问题补充：[/b]
想要用超链接的方式实现ajax提交，可是要如何在link_to_remote中应用loadItemByCatalog。

Answer 1

不是很清楚你想做什么,如果你是希望使用超连接的方式实现ajax提交,可以使用link_to_remote
[code="ruby"]
link_to_remote(name, options = {}, html_options = nil)
[/code]
[code="ruby"]
# Generates: Delete this post
link_to_remote "Delete this post", :update => "posts",
:url => { :action => "destroy", :id => post.id }

# Generates:
link_to_remote(image_tag("refresh"), :update => "emails",
:url => { :action => "list_emails" })
[/code]