Axis调用webservice中遇到的问题，请指教。

Question

下面是产生的错误，不清楚怎么回事，有谁能帮忙解答一下，如需要提供其他内容，请回复，谢谢！
AxisFault
faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Client
faultSubcode:
faultString: could not get next sequence value; nested exception is org.hibernate.exception.SQLGrammarException: could not get next sequence value
faultActor:
faultNode:
faultDetail:
{http://xml.apache.org/axis/}stackTrace:could not get next sequence value; nested exception is org.hibernate.exception.SQLGrammarException: could not get next sequence value
at org.apache.axis.message.SOAPFaultBuilder.createFault(SOAPFaultBuilder.java:222)
at org.apache.axis.message.SOAPFaultBuilder.endElement(SOAPFaultBuilder.java:129)
at org.apache.axis.encoding.DeserializationContext.endElement(DeserializationContext.java:1087)
at org.apache.xerces.parsers.AbstractSAXParser.endElement(Unknown Source)
at org.apache.xerces.impl.XMLNSDocumentScannerImpl.scanEndElement(Unknown Source)
at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(Unknown Source)
at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
at org.apache.xerces.parsers.XMLParser.parse(Unknown Source)
at org.apache.xerces.parsers.AbstractSAXParser.parse(Unknown Source)
at org.apache.xerces.jaxp.SAXParserImpl$JAXPSAXParser.parse(Unknown Source)
at org.apache.xerces.jaxp.SAXParserImpl.parse(Unknown Source)
at org.apache.axis.encoding.DeserializationContext.parse(DeserializationContext.java:227)
at org.apache.axis.SOAPPart.getAsSOAPEnvelope(SOAPPart.java:696)
at org.apache.axis.Message.getSOAPEnvelope(Message.java:435)
at org.apache.axis.transport.http.HTTPSender.readFromSocket(HTTPSender.java:796)
at org.apache.axis.transport.http.HTTPSender.invoke(HTTPSender.java:144)
at org.apache.axis.strategies.InvocationStrategy.visit(InvocationStrategy.java:32)
at org.apache.axis.SimpleChain.doVisiting(SimpleChain.java:118)
at org.apache.axis.SimpleChain.invoke(SimpleChain.java:83)
at org.apache.axis.client.AxisClient.invoke(AxisClient.java:165)
at org.apache.axis.client.Call.invokeEngine(Call.java:2784)
at org.apache.axis.client.Call.invoke(Call.java:2767)
at org.apache.axis.client.Call.invoke(Call.java:2443)
at org.apache.axis.client.Call.invoke(Call.java:2366)
at org.apache.axis.client.Call.invoke(Call.java:1812)
[b]问题补充：[/b]
谢谢xuxiaolei的回复，我看到faultCode: {http://schemas.xmlsoap.org/soap/envelope/}Client 这个，这个是不是说是客户端产生的问题，可是我客户端并没有用hibernate，怎么会有could not get next sequence value; nested exception is org.hibernate.exception.SQLGrammarException: 的异常呢？
异常是在程序代码中java.lang.Object _resp = _call.invoke(new java.lang.Object[] {in0});这行发生的。这些有说明什么呢？谢谢！

Answer 1

nested exception is org.hibernate.exception.SQLGrammarException: could not get next sequence value
应该是client端或service端中hibernate取得sequence出现的异常。检查下你的hibernate中取得sequence部分的配置代码吧。