ext tree 怎么获得当前树所有得节点 怎么获得所有得叶子节点呢？

Question

ext tree 怎么获得当前树所有得节点 怎么获得所有得叶子节点呢？

Answer 1

[b]Node[/b]
cascade( Function fn, [Object scope], [Array args] ) : void

Cascades down the tree from this node, calling the specified function with each node. The scope (this) of function call will be the scope provided or the current node. The arguments to the function will be the args provided or the current node. If the function returns false at any point, the cascade is stopped on that branch.

[b]Parameters:[/b]
fn : Function
The function to call
scope : Object
(optional) The scope of the function (defaults to current node)
args : Array
(optional) The args to call the function with (default to passing the current node)

[b]Returns:[/b]
void