（接口编程）dom4j怎么实现读取XMl文件后变成一个类，建立文件，里面还有属性的那种

Question

RT

有高手请短消息留下E-mail
求。。。。

public void readerRoot() {
    try {
        xmlFile = new File(url);
        SAXReader reader = new SAXReader();
        document = reader.read(xmlFile);
    } catch (DocumentException e) {
        e.printStackTrace();
    }
    Element root = document.getRootElement();

// System.out.println(root.getNodeTypeName());
List list = root.elements();
{
// for (int i = 0; i < list.size(); i++) {
// Element e = (Element) list.get(i);
// System.out.println("1------" + e.getData());
// }
for(Element level2: list){
System.out.println(level2.getName());
}
}
}

怎么样把level2.getName());的内容发出去。。。。。

还有，接口编程怎么写啊？

Answer 1

[code="java"]
public interface Result {
public Date getDate();
public List getNames();
}
public class ResultImpl implements Result {
private Date date;
private List names;
public ResultImpl() {
names = new ArrayList();
}
public Date getDate() {
return this.date;
}
public List getNames() {
return new ArrayList(this.names);
}
public void addNames(List names) {
this.names.addAll(names);
}
public void addName(String name) {
this.names.add(name);
}
public int size() {
return this.names.size();
}
public void clear() {
this.names.clear();
}
}

public Result readerRoot() {
ResultImpl result = new ResultImpl();
try {
xmlFile = new File(url);
SAXReader reader = new SAXReader();
document = reader.read(xmlFile);
} catch (DocumentException e) {
e.printStackTrace();
}
Element root = document.getRootElement();
// System.out.println(root.getNodeTypeName());
List list = root.elements();
{
// for (int i = 0; i < list.size(); i++) {
// Element e = (Element) list.get(i);
// System.out.println("1------" + e.getData());
// }
for(Element level2: list){
System.out.println(level2.getName());
result.addName(level2.getName());
}
}
return result;
}

Result result = readerRoot();
List list = result.getNames();
[/code]