ruby 循环的一个问题

Question

[code="ruby"]
def aa
a = [1,2,3]
result = []
for i in a
puts i
result << lambda {i}
end

result
end

def bb
a = [1,2,3]
result = []
a.each {|j|
result << lambda {j}
}
result
end

puts aa[0].call #3
puts bb[0].call #1

[/code]

为什么第一种循环方式，数组中每个lambda的参数都是3呢？

Answer 1

http://2015.iteye.com/blog/639234 看完就应该明白了