php文件代码如下
<?php error_reporting(0);
header ('Content-Type: text/json');
$key=$_GET['key'];
$handle = fopen ("https://www.xxx.xxx/proxy/list/download/$key/-/socks/port/direct/", "rb");
$contents = "";
do {
$data = fread($handle, 1024);
if (strlen($data) == 0) {
break;
}
$contents.= $data;
} while(true);
fclose ($handle);
echo $contents;
$contents 返回2种结果,返回结果如下, 目的是判断如果返回结果是2,就把结果2返回的所有信息替换成 空白,返回是结果1就正常显示,请教应该怎么写 ????
返回结果1
45.72.40.64:9158:sd3gwerg:3wetdg
45.224.255.124:9690:sd3gwerg:3wetdg
104.144.34.3:7587:sd3gwerg:3wetdg
45.57.252.126:8662:sd3gwerg:3wetdg
138.128.107.238:8827:sd3gwerg:3wetdg
138.128.114.182:7748:sd3gwerg:3wetdg
返回结果2
<!DOCTYPE html>
<html lang="en">
<head>
<title>Page Not Found</title>
<meta name="description" content="">
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
$contents 返回2种结果,返回结果如下, 目的是判断如果返回结果是2,就把结果2返回的所有信息替换成 空白,返回是结果1就正常显示,请教应该怎么写 ????