tkinter窗口不能够嵌套吗？为什么导入第二个tkinter窗口后点击按钮会无效

Question

• 第一段是验证码（vcode.py）

• import string,random
  vcode=''
  words=''.join((string.ascii_letters,string.digits))
  for i in range(6):
      vcode+=random.choice(words)

•  第二段是登陆界面框架

  • import tkinter as tk
    import vcode
    
    window=tk.Tk()
    window.title("PY系统登陆界面")
    sw=window.winfo_screenwidth()
    sh=window.winfo_screenheight()
    w=310;h=160
    x=(sw-w)/2;y=(sh-h)/2
    window.geometry("%dx%d+%d+%d"%(w,h,x,y))
    
    tk.Label(window,text='用户账号：').grid(row=0,column=0)
    tk.Label(window,text='用户密码：').grid(row=1,column=0)
    tk.Label(window,text='验 证 码：').grid(row=2,column=0)
    tk.Label(window,text='%s'%vcode.vcode).grid(row=3,column=1)
    
    usr=tk.StringVar();pwd=tk.StringVar();vcode=tk.StringVar()
    
    e1=tk.Entry(window,textvariable=usr).grid(row=0,column=1,pady=5)
    e2=tk.Entry(window,textvariable=pwd,show='*').grid(row=1,column=1,pady=5)
    e3=tk.Entry(window,textvariable=vcode).grid(row=2,column=1,pady=5)
    
    def tip():
        print("用户账号:",usr.get())
        print("用户密码:",pwd.get())
    def login():
        import login
        
    loginbt=tk.Button(window,text='注册',width=12,command=login).grid(row=4,column=0,sticky=tk.W,padx=10,pady=10)
    logonbt=tk.Button(window,text='登录',width=12,command=window.destroy).grid(row=4,column=1,sticky=tk.E,padx=10,pady=10)
    
    tk.mainloop()
    
    ​

    第三段(login.py，在第二段中导入的正是这一段)原目的是想加入一个注册的窗口，但是导入后点击注册或者清除都没有反应

  • import tkinter as tk
    
    logwindow=tk.Tk()
    logwindow.title("PY系统账号注册")
    sw=logwindow.winfo_screenwidth()
    sh=logwindow.winfo_screenheight()
    w=310;h=115
    x=(sw-w)/2;y=(sh-h)/2
    logwindow.geometry("%dx%d+%d+%d"%(w,h,x,y))
    
    tk.Label(logwindow,text='用户账号：').grid(row=0,column=0)
    tk.Label(logwindow,text='用户密码：').grid(row=1,column=0)
    
    logusr=tk.StringVar();logpwd=tk.StringVar();
    
    logusre=tk.Entry(logwindow,textvariable=logusr).grid(row=0,column=1,padx=10,pady=5)
    logpwde=tk.Entry(logwindow,textvariable=logpwd).grid(row=1,column=1,padx=10,pady=5)
    
    def tip():
        print("用户账号:",logusr.get())
        print("用户密码:",logpwd.get())
    def cancel():
        logusr.set('')
        logpwd.set('')
    
    tk.Button(logwindow,text='注册',width=12,command=tip).grid(row=3,column=0,sticky=tk.W,padx=10,pady=10)
    tk.Button(logwindow,text='清除',width=12,command=cancel).grid(row=3,column=1,sticky=tk.E,padx=10,pady=10)
    
    tk.mainloop()
    

    

    （自学阶段实在很多不理解，可轻喷，请各路大神不吝赐教）

Answer 1

在你的代码基础上进行修改，结合sqlite3库，将新注册用户存入数据库，根据用户输入情况进行校验。完整代码：

import random
import string
import tkinter as tk
import sqlite3
from tkinter.messagebox import showinfo, showwarning, showerror
window = tk.Tk()
window.title("PY系统登陆界面")
sw = window.winfo_screenwidth()
sh = window.winfo_screenheight()
w = 310
h = 160
x = (sw-w)/2
y = (sh-h)/2
window.geometry("%dx%d+%d+%d" % (w, h, x, y))

vcode = ''
words = ''.join((string.ascii_letters, string.digits))
for i in range(6):
    vcode += random.choice(words)

tk.Label(window, text='用户账号：').grid(row=0, column=0)
tk.Label(window, text='用户密码：').grid(row=1, column=0)
tk.Label(window, text='验 证 码：').grid(row=2, column=0)
tk.Label(window, text='%s' % vcode).grid(row=3, column=1)

usr = tk.StringVar()
pwd = tk.StringVar()
v_code = tk.StringVar()

e1 = tk.Entry(window, textvariable=usr).grid(row=0, column=1, pady=5)
e2 = tk.Entry(window, textvariable=pwd, show='*').grid(row=1, column=1, pady=5)
e3 = tk.Entry(window, textvariable=v_code).grid(row=2, column=1, pady=5)


def check():
    name = usr.get()
    psw=pwd.get()
    check=v_code.get()
    print("用户账号:", name)
    print("用户密码:",psw )
    conn = sqlite3.connect('users.db')
    cur = conn.cursor()
    sq='select name from users;'
    sq1 = 'select password from users;'
    if name not in [x[0] for x in cur.execute(sq)] or psw not in [x[0] for x in cur.execute(sq1)] or check!=vcode:
        showerror(title='Error',message='Invalid username or password or checkcode! Please input again!')
    else:
        showinfo(title='OK',
                  message=f'Welcome {name}!')


def login():
    logwindow = tk.Tk()


    logwindow.title("PY系统账号注册")
    sw = logwindow.winfo_screenwidth()
    sh = logwindow.winfo_screenheight()
    w = 310
    h = 115
    x = (sw-w)/2
    y = (sh-h)/2
    logwindow.geometry("%dx%d+%d+%d" % (w, h, x, y))

    tk.Label(logwindow, text='用户账号：').grid(row=0, column=0)
    tk.Label(logwindow, text='用户密码：').grid(row=1, column=0)

    logusr = tk.StringVar()
    logpwd = tk.StringVar()

    logusre = tk.Entry(logwindow, textvariable=logusr)
    logusre.grid(
        row=0, column=1, padx=10, pady=5)
    logpwde = tk.Entry(logwindow, textvariable=logpwd)
    logpwde.grid(
        row=1, column=1, padx=10, pady=5)

    def tip():
        
        print("用户账号:", logusre.get())
        print("用户密码:", logpwde.get())
        conn=sqlite3.connect('users.db')
        cur=conn.cursor()
        #cur.execute('drop table if exists users;')
        
        cur.execute(
            'create table if not exists users(id integer autoincreament,name text,password text);')
        s2='insert into users(name,password) values(?,?);'
        cur.execute(s2, [logusre.get(), logpwde.get()])
        
        conn.commit()
    
    tk.Button(logwindow, text='注册', width=12, command=tip).grid(
        row=3, column=0, sticky=tk.W, padx=10, pady=10)
    tk.Button(logwindow, text='退出', width=12, command=logwindow.destroy).grid(
        row=3, column=1, sticky=tk.E, padx=10, pady=10)

    logwindow.mainloop()


loginbt = tk.Button(window, text='注册', width=10, command=login).grid(
    row=4, column=0, sticky=tk.W, padx=8, pady=10)
logonbt = tk.Button(window, text='登录', width=10, command=check).grid(
    row=4, column=1, sticky=tk.E, padx=8, pady=10)
logonbt = tk.Button(window, text='退出', width=10, command=window.destroy).grid(
    row=4, column=2, sticky=tk.E, padx=8, pady=10)
window.mainloop()