将对象数组a中不包含数组b里的元素的项去除

Question

var a = [
        { name: "aa", children: [{ name: "aa1" }, { name: "aa2" }] },
        { name: "bb", children: [{ name: "bb1" }, { name: "bb2" }] },
        { name: "cc", children: [{ name: "cc1" }, { name: "cc2" }] },
        { name: "dd", children: [{ name: "dd1" }, { name: "dd2" }] },
        { name: "ee", children: [{ name: "ee1" }, { name: "ee2" }] },
      ];
var b = ["aa1","aa2","cc1", "bb2","dd1" ];
//目标对象
var mune = [
        { name: "aa", children: [{ name: "aa1" },{ name: "aa2" }] },
        { name: "bb", children: [{ name: "bb2" }] },
        { name: "cc", children: [{ name: "cc1" }] },
        { name: "dd", children: [{ name: "dd1" }] },
      ];

Answer 1

var a = [

        { name: "aa", children: [{ name: "aa1" }, { name: "aa2" }] },

        { name: "bb", children: [{ name: "bb1" }, { name: "bb2" }] },

        { name: "cc", children: [{ name: "cc1" }, { name: "cc2" }] },

        { name: "dd", children: [{ name: "dd1" }, { name: "dd2" }] },

        { name: "ee", children: [{ name: "ee1" }, { name: "ee2" }] },

      ];

var b = ["aa1","aa2","cc1", "bb2","dd1" ];

 

for(var i=0;i<a.length;i++){

  for(var j=0;j<a[i].children.length;j++){

    if(b.indexOf(a[i].children[j].name)==-1){

      a[i].children.splice(j,1);

      j--;

    }

  }

  if(a[i].children.length==0){

    a.splice(i,1);

    i--;

  }

}