import pandas as pd
import numpy as np
df = pd.DataFrame([[1,np.nan,3],[4,np.nan,6],[7,8,9]])
print(df)
期望的结果:
3和6移到前一列,并用“否”替换之
import pandas as pd
import numpy as np
df = pd.DataFrame([[1,np.nan,3],[4,np.nan,6],[7,8,9]])
print(df)
期望的结果:
3和6移到前一列,并用“否”替换之
我费劲给你写了朋友,采纳给我不过分把?
import pandas as pd
import numpy as np
df = pd.DataFrame([[1,np.nan,3],[4,np.nan,6],[7,8,9]])
print(df)
# 转层矩阵,让NAN右移动,行遍历
matrix = df.values
for m in range(len(matrix)):
row = matrix[m]
for x in range(len(row)):
if np.isnan(row[x]):
if x == len(row)-1:
pass
else:
matrix[m] = np.concatenate([row[:x], row[x+1:] , row[x:x+1]],axis=0)
df_ = pd.DataFrame(matrix)
df_.columns = df.columns
print(df_)
# 替换nan
df_ = df_.fillna('否')
print(df_)
输出展示:
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