死锁的问题

Question

public class TestDeadLock{
static Object O1 = new Object ();
static Object O2 = new Object ();
public static void main(String args[]){
Runner6 T1 = new Runner6();
Runner6 T2 = new Runner6();
T1.flag = false;
T1.start();
T2.start();
}
}

class Runner6 extends Thread{
public boolean flag = true;
public void run(){

    if(flag){
    synchronized(TestDeadLock.O1){
        System.out.println("O1锁住了");
        try{sleep(1000);}catch(InterruptedException e){}
        }
    synchronized(TestDeadLock.O2){
        System.out.println("2");
        }
 } 
 else{
    synchronized(TestDeadLock.O2){
                System.out.println("O2锁住了");
        try{sleep(1000);}catch(InterruptedException e){ }
        }       
    synchronized(TestDeadLock.O1){
        System.out.println("1");
        }
    }

    }
}   

怎么把这串代码搞成死锁？

Answer 1

[code="java"]

给个采纳！！！！！！！！！！！！！！！！！！！！！！！！！！！！！！

[/code]

Answer 2

[code="java"]

给你一个例子：

package cn.com.io.threadDemo.ThreadSyn;

/**

• 通过两个属性值创建死锁
• 本程序通过两个线程各自锁定一个属性值，这样两个线程都无法结束，造成死锁

• @author Administrator
  *
  */
  public class ThreadSyn2 implements Runnable{

  private static Object obj1=new Object();

  private static Object obj2=new Object();

  /**

  • @param args */ public static void main(String[] args) { ThreadSyn2 ts1=new ThreadSyn2(); ThreadSyn2 ts2=new ThreadSyn2();

  Thread t1=new Thread(ts1);//线程1
  Thread t2=new Thread(ts2);//线程2
  t1.setName("theOne");
  t2.setName("theTwo");

  t1.start();
  t2.start();

  }

  public void run() {
  String name=Thread.currentThread().getName();
  if(name.equals("theOne")){
  method1(name);
  }else{
  method2(name);
  }

  }

  //线程1的方法锁定obj1，线程2就无法完成
  private void method1(String name) {
  System.out.println(name);
  synchronized(obj1){
  try {
  Thread.sleep(1000);
  } catch (InterruptedException e) {
  e.printStackTrace();
  }
  synchronized(obj2){
  System.out.println(obj2);
  }
  
  }
  
  }

  //线程1的方法锁定obj2，线程1就无法完成
  private void method2(String name) {
  System.out.println(name);
  synchronized(obj2){
  try {
  Thread.sleep(1000);
  } catch (InterruptedException e) {
  e.printStackTrace();
  }
  synchronized(obj1){
  System.out.println(obj1);
  }
  }
  
  }
  }

[/code]

Answer 3

最简单了 你把每个synchronized里面都加个相应的
TestDeadLock.O2.wait()或者TestDeadLock.O1.wait()就行了 :wink: