「已注销」 2021-03-18 14:53 采纳率: 33.3%
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已结题

把list放进map中

有个这样的List<PerformanceRanking> list PerformanceRanking是实体类,从数据库查询出来的,相当于一个map

把list放进map中 Map<String,List<PerformanceRanking>> 我想把这个map按照实体类中的三个字段作为String。该如何实现呢

 

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  • 哆啦A梦丶幻想 2021-03-19 10:43
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        class A {
            private String id;
            private String address;
            private int age;
            private boolean sex;
    
            public String getId() {
                return id;
            }
    
            public void setId(String id) {
                this.id = id;
            }
    
            public String getAddress() {
                return address;
            }
    
            public void setAddress(String address) {
                this.address = address;
            }
    
            public int getAge() {
                return age;
            }
    
            public void setAge(int age) {
                this.age = age;
            }
    
            public boolean isSex() {
                return sex;
            }
    
            public void setSex(boolean sex) {
                this.sex = sex;
            }
    
            public A(String id, String address, int age, boolean sex) {
                this.id = id;
                this.address = address;
                this.age = age;
                this.sex = sex;
            }
        }
        @Test
        public void testA() {
            List<A> aList = new ArrayList<>();
            A a1 = new A("1", "地址1", 10, false);
            aList.add(a1);
            A a2 = new A("1", "地址1", 10, true);
            aList.add(a2);
            A a3 = new A("2", "地址2", 12, false);
            aList.add(a3);
            A a4 = new A("2", "地址2", 12, true);
            aList.add(a4);
    
            Map<String, List<A>> map = aList.stream().collect(Collectors.groupingBy(a -> a.id+"_"+a.address+"_"+a.age, Collectors.toList()));
            System.out.println(map);
        }
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