weixin_42405362 2011-10-19 17:31
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关于通过POST方法获得参数的问题

[color=darkred]页面:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">


New Document






服务端获取代码是: public ActionForward jsonImpl(ActionMapping mapping,ActionForm form,
HttpServletRequest request, HttpServletResponse response) throws IOException
{
ServletInputStream sis = request.getInputStream();
DataInputStream dataInStream = new DataInputStream(sis);
byte[] buf = new byte[1024];
ByteArrayOutputStream os = new ByteArrayOutputStream();
int n = dataInStream.read(buf);
while (n != -1) {
os.write(buf, 0, n);
n = dataInStream.read(buf);
}
byte[] res = os.toByteArray();
System.out.println(new String(res));
}
发现无法从页面获得text中得value值:{"modelname":"electricity_charge","userval":"3202008281"}

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6条回答

  • aini3456 2011-10-19 17:37
    关注

    你将
    modelname
    electricity_charge
    userval
    作为参数传递吧

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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