xpath 获取当前节点标签名

Question

r = requests.get('https://www.baidu.com/', headers={"User-Agent": UserAgent().random})
html = etree.HTML(r.content.decode('utf-8', 'ignore'))
span_tag = html.xpath("//span[@class='big']/*")
for i in span_tag:
    print(i.tag)
    print(i.xpath("./name()"))

假设有这么一个网页，我获取到了class为big的全部子节点，我想获取全部子节点的标签名，如何获取？

尝试过.tag和./name都获取不了

Answer 1

from lxml import etree
html = "world"
a = etree.HTML(html)
print(a.xpath("local-name(//a[@id='1'])"))
print(a.xpath("//a[@id='1']")[0].tag)