有些源代码有四个a标签,有的只有两个 或者三个a标签如何正则抓?

Question

html = '''<dl class="bigtr cl">
  <dt class="li01 ta_c"><b class="nob1">3</b></dt>
  <dt class="li02"><samp class="holdPIC"></samp></dt>
  <dt class="li03 oh"><a href="https://www.1905.com/vod/play/516604.shtml" target="_blank" title="杨贵妃" class=" pl28">杨贵妃</a></dt>
  <dt class="li04 oh"><span><a href="https://www.1905.com/mdb/star/2996732/" target="_blank" title="周洁">周洁</a>/<a href="https://www.1905.com/mdb/star/1973493/" target="_blank" title="刘文治">刘文治</a>/<a href="https://www.1905.com/mdb/star/1403/" target="_blank" title="濮存昕">濮存昕</a>/<a href="https://www.1905.com/mdb/star/2998726/" target="_blank" title="程文宽">程文宽</a></span></dt>
  <dt class="li05 ta_c"><span>39,189</span></dt>
</dl>


                              <dl class="cl">
  <dt class="li01 ta_c"><b class="ptnob">5</b></dt>
  <dt class="li02"><samp class="holdPIC"></samp></dt>
  <dt class="li03 oh"><a href="https://www.1905.com/vod/play/85426.shtml" target="_blank" title="神话" class=" pl28">神话</a></dt>
  <dt class="li04 oh"><span><a href="https://www.1905.com/mdb/star/242/" target="_blank" title="成龙">成龙</a>/<a href="https://www.1905.com/mdb/star/596/" target="_blank" title="金喜善">金喜善</a>/<a href="https://www.1905.com/mdb/star/1297/" target="_blank" title="梁家辉">梁家辉</a>/<a href="https://www.1905.com/mdb/star/1935/" target="_blank" title="于荣光">于荣光</a></span></dt>
  <dt class="li05 ta_c"><span>34,348</span></dt>
</dl>
                              <dl class="cl">
  <dt class="li01 ta_c"><b class="ptnob">6</b></dt>
  <dt class="li02"><samp class="holdPIC"></samp></dt>
  <dt class="li03 oh"><a href="https://www.1905.com/vod/play/85340.shtml" target="_blank" title="我和姐姐" class=" pl28">我和姐姐</a></dt>
  <dt class="li04 oh"><span><a href="https://www.1905.com/mdb/star/3065837/" target="_blank" title="张梦露">张梦露</a>/<a href="https://www.1905.com/mdb/star/3406/" target="_blank" title="刘洋">刘洋</a>/<a href="https://www.1905.com/mdb/star/3065838/" target="_blank" title="易含">易含</a></span></dt>
  <dt class="li05 ta_c"><span>30,709</span></dt>
  </dl>
  '''

如题, 如果都四位演员,我能正常抓, 如果少几个演员,或者多几个演员, 如何用正则抓取, 我写了一个长长的正则, 只能固定抓四位的

import requests, re




def one_page(url):
    response = requests.get(url)
    if response.status_code == 200:
        #         response.encoding = 'utf8'
        return response.text
    return None


def parse_one_page(html):
    partter = re.compile(
        '<dl.*?"li01 ta_c".*?".*?">(.*?)</b>.*?"li03.*?href="(.*?)".*?pl28">(.*?)</a>.*?"li04.*?<a.*?>(.*?)</a>.*?<a.*?>(.*?)</a>.*?<a.*?>(.*?)</a>.*?<a.*?>(.*?)</a>.*?"li05.*?<span>(.*?)</span></dt>.*?</dl>',
        re.S)
    items = re.findall(partter, html)
    print(items)


def main():
    url = 'https://www.1905.com/vod/rank/tao1.shtml'
    html = one_page(url)

    parse_one_page(html)


if __name__ == '__main__':
    main()

结果 很多都漏抓了, 小白刚学习, 请高人指教

Answer 1

import requests, re


def one_page(url):
    response = requests.get(url)
    if response.status_code == 200:
        #         response.encoding = 'utf8'
        return response.text
    return None
def parse_one_page(html):
    partter = re.compile(
        '<dl.*?"li01 ta_c".*?".*?">(.*?)</b>.*?"li03.*?href="(.*?)".*?pl28">(.*?)</a>.*?"li04.*?<span>(.*?)</span>.*?"li05.*?<span>(.*?)</span></dt>.*?</dl>',
        re.S)
    items = re.findall(partter, html)
    for i, item in enumerate(items):
        r = list(item)
        r[3] = re.findall(r'>(.*?)</a>', r[3])
        items[i] = r
    print(items)

def main():
    url = 'https://www.1905.com/vod/rank/tao1.shtml'
    html = one_page(url)
    parse_one_page(html)

if __name__ == '__main__':
    main()