在拷贝赋值函数里调用析构函数和拷贝构造函数可行吗

Question

class Matrix
{
public:
    Matrix(int m, int n) : _m(m), _n(n), _array(new int[m * n]) {}

    Matrix(const Matrix &other)
        : _m(other._m), _n(other._n), _array(new int[_m * _n]) {}
    Matrix(Matrix &&other) : _m(other._m), _n(other._n), _array(other._array)
    {
        other._m = 0, other._n = 0, other._array = nullptr;
    }

    Matrix &operator=(const Matrix &other)
    {
        this->~Matrix();
        new (this) Matrix(other);
    }
    Matrix &operator=(Matrix &&other)
    {
        this->~Matrix();
        new (this) Matrix(std::move(other));
    }

    ~Matrix()
    {
        delete[] _array;
    }

private:
    int _m, _n;
    int *_array;
}

Answer 1

能，为什么不能。不过要在析构前检测下目标与本身是否是同一实例；不然析构了就完犊子了。